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具有一维常量的二维数组的delete []释放内存

[英]memory deallocation with delete [] for 2d array with one dimension constant

I allocated a 2D array using new like this 我像这样使用new分配了2D数组

  int (*arr)[2] = new int[x][2];

x is calculated at runtime. x在运行时计算。

How should I deallocate this memory? 我应该如何释放该内存? I tried 我试过了

delete [] *arr[0];
delete [] *arr[1]; 

However, valgrind says that their were 13 allocs and 14 frees. 但是,valgrind说他们有13个分配器和14个释放器。

You use one new[] , so you should use one delete[] : 您使用一个new[] ,所以您应该使用一个delete[]

delete[] arr;

The delete[] form applies to any new[] ; delete[]表格适用于任何new[] there aren't separate cases for new T[x] as for new T[x][2] or anything. 有不单独箱子new T[x]new T[x][2]或任何东西。 An expression like new T[x][2] is actually a single array new where the array element has type "array of 2 T's". new T[x][2]这样的表达式实际上是一个new数组,其中array元素的类型为“ 2个T的数组”。

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