PHP如何将参数传递给常量

Question

I'm looking for a solution to pass arguments to a dynamic constant Name.

 <?php 
 class L {
   const profile_tag_1 = 'Bla bla Age from %s to %s';
   const profile_tag_2 = 'Wow Wow Age from %s to %s';

   public static function __callStatic($string, $args) {
      return vsprintf(constant("self::" . $string), $args);
   }
 }

My code

 $x = 1;
 echo constant("L::profile_tag_".$x); // arguments: 20, 30

I want get

 Bla bla Age from 20 to 30

How can I pass my two arguments to it?

Answer 1

You can use func_get_args() and array_shift() to isolate the constant string name.
[ Codepad live ]

<?php 
 class L {
   const profile_tag_1 = 'Bla bla Age from %s to %s';
   const profile_tag_2 = 'Wow Wow Age from %s to %s';

   public static function __callStatic() {
      $args = func_get_args();
      $string = array_shift($args);
      return vsprintf(constant('self::' . $string), $args);
   }
 }


L::__callStatic('profile_tag_1',12,12);

But, be aware when using this function with a generic call to a static method, you need to change __callStatic signature to allow $name and $arguments like this:

 class L {
   const profile_tag_1 = 'Bla bla Age from %s to %s';
   const profile_tag_2 = 'Wow Wow Age from %s to %s';

   public static function __callStatic($name, $args) {
      $string = array_shift($args);
      return vsprintf(constant('self::' . $string), $args);
   }
 }


L::format('profile_tag_1',12,12);

A better way

Although, there is a better way to perform what you need (read Yoshi in comments), considering you are using everything static:

 echo sprintf(L::profile_tag_1,12,14);

You don't even need a Class at this point.

Answer 2

试试这个：

echo L::__callStatic("profile_tag_".$x, array(20, 30));