在T-SQL中，用一个字符替换字符串中的字母，用另一个字符替换数字

Question

I have string like ' A9Tf6Uv54 ', Now I want replace it with ' xzxxzxxzz ' format.

In other words alphabetic characters are replaced with ' x ' and numbers with ' z '.

How can I replace both numeric and alphabets with different character in SQL?

Answer 1

You can do like this:

DECLARE @StringText VARCHAR(20) =  'A9Tf6Uv54';
DECLARE @digitReplacement VARCHAR(20) =  'z';
DECLARE @letterReplacement VARCHAR(20) =  'x';

WHILE PATINDEX('%[^0-9'+@letterReplacement+']%',@StringText)>0
    SET @StringText = STUFF(@StringText,PATINDEX('%[^0-9'+@letterReplacement+']%',@StringText),1,@letterReplacement)
WHILE PATINDEX('%[0-9]%',@StringText)>0
    SET @StringText = STUFF(@StringText,PATINDEX('%[0-9]%',@StringText),1,@digitReplacement)


--RESULT
xzxxzxxzz

Answer 2

ifound bug and fix it -:)

declare @r int=1  --pointer to next letter in the string
declare @l int = (select len('A9Tf6Uv54'))
declare @str varchar(100)=''   -- init the new str
declare @x varchar(10)='x'  --replace number
declare @z varchar(10)='z'  --replace char
while @l!=0    --loop ending at the end of the original str
begin
if (ascii(substring('A9Tf6Uv54',@r,1)) between 48 and 57)

begin
set @str=ltrim(@str)+@z
set @l=@l-1
set @r=@r+1
end
else
begin
set @str=ltrim(@str)+@x
set @l=@l-1
set @r=@r+1
end
end
select @str

>