将浮点双精度转换为非浮点字符串

Question

I have the following number:

1.0645208E10 , which is in my case a double value. I would like to convert it into 106.45 .

Any recommendation how to get 106.45 ?

I appreciate your answers!

Answer 1

You can try this:

    double bigDouble = 1.0645208E10;
    String strDouble = String.format(Locale.ENGLISH, "%.2f", bigDouble/100000000);
    System.out.println(strDouble);

It will give you 106.45

But be aware of the fact that the output has nothing to do with the original value!! Is one hundred million times smaller...

Answer 2

Any recommendation how to get 106.45?

If you want to get only output then you can do following.

Double d = 1.0645208E10;
String s = d.toString().replace(".", "");//Converts into string and removes dot (.)
String s1 = s.substring(0, 5);//it gets only first 5 characters 
String s2 = s1.substring(0, 3) + "." + s1.substring(3, 5);//it adds decimal point after first 3 character
System.out.println("Expected Output: " + s2);