[英]gulp-watch doesn't update gulp-jshint
what's wrong with this code: 这段代码有什么问题:
var gulp = require('gulp');
var watch = require('gulp-watch');
var connect = require('gulp-connect');
var jshint = require('gulp-jshint');
var stylish = require('jshint-stylish');
//lint
module.exports = gulp.task('lint', function () {
return gulp.src([config.paths.src.scripts,config.paths.exclude.bower])
.pipe(jshint())
.pipe(jshint.reporter(stylish));
});
//watch
module.exports = gulp.task('watch', function () {
watch(config.paths.src.scripts, ['lint'])
.pipe(connect.reload());
watch(config.paths.src.templates, ['templates'])
.pipe(connect.reload());
watch(config.paths.src.index)
.pipe(connect.reload());
});
when ie I edit a js file doing an error jshint show me nothing. 当我编辑一个js文件时出错jshint给我什么都没有。
This works: 这有效:
watch(config.paths.src.scripts)
.pipe(jshint())
.pipe(jshint.reporter(stylish))
.pipe(connect.reload());
but it's quite the same or not ? 还是完全一样?
gulp-watch does not support an array of task names like the internal gulp.watch. gulp-watch不支持内部gulp.watch之类的任务名称数组。 See documentation at https://www.npmjs.org/package/gulp-watch
请参阅https://www.npmjs.org/package/gulp-watch上的文档
You have to provide gulp-watch a function, something like 您必须提供gulp-watch功能,例如
watch(config.paths.src.scripts, function(events, done) {
gulp.start(['lint'], done);
}
Note: It seems that gulp.start will be deprecated in Gulp 4.x, it will be replaced by a task runner called bach: https://github.com/floatdrop/gulp-watch/issues/92 注意:似乎gulp.start将在Gulp 4.x中被弃用,它将由一个名为bach的任务运行程序代替: https : //github.com/floatdrop/gulp-watch/issues/92
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