用gulp-jshint进行gulp-ignore

Question

I want to do a jshint on the files that is not library files like require js

var gulp = require('gulp');

var jshint = require('gulp-jshint');
var ignore = require('gulp-ignore');
gulp.task('jshint', function() {
  gulp.src('./js/src/*.js')
     .pipe(ignore.exclude('require.js'))
     .pipe(jshint())
     .pipe(jshint.reporter('default'));
});

This still reports require js

 C:\Work\neolivz\js\src\require.js: line 12, col 267, Too many errors. (32% scanned).

Any idea?

Answer 1

您还可以创建一个.jshintignore文件，就像.gitignore一样，其中包含要忽略的文件。

Answer 2

I think you should be able to pass a regex to gulp ignore if using a specific path isn't working:

var gulp = require('gulp');

var jshint = require('gulp-jshint');
var ignore = require('gulp-ignore');
gulp.task('jshint', function() {
  gulp.src('./js/src/*.js')
     .pipe(ignore.exclude(/require\.js/))
     .pipe(jshint())
     .pipe(jshint.reporter('default'));
});