如何放松Gulp-JSHint的掉毛规则？

Question

I'm trying to adjust the gulp-jshint 'fail' reporter to only fail based on situations that would break javascript code when minifying.

For example the two situations I find cause the most problems are

• Missing Semicolons

• Implicitly declared variables

Is there any way I can create a gulp-jshint task that only looks for the above conditions?

So far I have:

gulp.task('lint', function() {
    return gulp.src('src/main/webapp/static/js/**/**/**/*')
            .pipe(jshint())
            .pipe(jshint.reporter('fail'));
});

But this picks up many issues that aren't important for minification

---

EDIT

I have tried using:

.pipe(jshint.reporter('default', {undef: true, asi: false}))

but this doesn't seem to change anything

Answer 1

From looking at the docs , the conditions you want to enforce are the following:

undef : This option prohibits the use of explicitly undeclared variables. This option is very useful for spotting leaking and mistyped variables.

and

asi : This option suppresses warnings about missing semicolons. There is a lot of FUD about semicolon spread by quite a few people in the community. The common myths are that semicolons are required all the time (they are not) and that they are unreliable. JavaScript has rules about semicolons which are followed by all browsers so it is up to you to decide whether you should or should not use semicolons in your code.

So you should have

1. undef = true

and

2. asi = false