gulp-jshint软件包：如何发送参数（不带.jshintrc文件）？

Question

I'm currently trying to migrate a grunt project to a gulp project. Actually, in the gruntfile I have (for the jshint task) something like this:

jshint: { options: { trailing:true, evil:false, indent:4, undef:true, unused:true, node:false, browser:false, loopfunc:true, devel:false }, default: { options: { browser:true, globals: { define:true } }, src: [basePath + "js/**/*.js"] } }

So, when I write "grunt jshint" in the terminal it seems to work fine. However, in the gulpfile I wrote this:

gulp.task("jshint", function() { return gulp.src( basePath + "js/**/*.js" ) .pipe( jshint( { "trailing": true,..., "globals": true } ) ) .pipe( jshint.reporter("default") ); });

But when I write "gulp jshint" in terminal, it crashes.

My question is: Is there a way to send jshint parameters without .jshintrc file with the gulp-jshint node package? (I've already read the documentation in the npm site, but I dont undestand the "lookup" option)

Answer 1

globals is an array, not true false, here is my example. lookup works just like you were thinking.

gulp.src(files.backend)
    .pipe(jshint({ "lookup": false, /* other options */ "globals": ['$']}))
    .pipe(jshint.reporter(stylish))
    .on('error', gutil.log);