在C＃中将十六进制数转换为2字节字符串表示法

Question

I am looking for the simplest way to achieve this :

num = 2376.75 => 0949 ( hex conversion of rounded off of 2376.5 to 2377).Num could be negative num ber as well.

I have very ugly code to do this which luckily works for me :

 val1 = 2376.75
    int val = Convert.ToInt16( Math.Round(val1));
    valStringLsb = ((byte)val ).ToString("X");
     if (valStringLsb.Length == 1)
    {

      valStringLsb = "0" + valStringLsb;
    }

    string valStringmsb = ((byte)(si >> 8)).ToString("X");
    int k = valStringmsb.Length;
    if (k == 1)
    {
       valStringmsb = "0" + valStringmsb;
    }
    else
    {

    valStringmsb = ((byte)(val >> 8)).ToString("X").Equals("0") ? "00" : (((byte)(val >> 8)).ToString("X")); 
    }

    valString += (valStringLsb + valStringmsb);

Is there any simple way or API to achieve this? The reason i want to do this is I want 0949 value not 949 value for 2377.

Answer 1

If you want to have simplicity you could use this:

Func<int, string> DecimalToHex = new Func<int, string>((input) => 
{
    return Convert.ToString(input, 16).PadLeft(4, '0');
});

The important part is the Convert so you don't have to use a Func<> method. If you want to use this approach, then you will have to supply your rounded number. You can not supply a double into this function directly.