如何在java中比较二维数组的2个元素？

Question

int turnCounter = 0;
public String [][] board = new String[3][3];


    public static int buttonClicked = 0;

    //this is going to check if there is a winning move
    public String winningCheck(){
        if (board[0][0] ==(board[0][1]) 
                && board[0][0]==(board[0][2])){
            message = (board[0][0] + " is the winner");
            gameOver = true;
        }
        return message;
    }


if (xTurn == true && twoIsChosen == false && gameOver == false){
        board[0][1] = "X";
        b01.setText(board[0][1]);
        if(turnCounter > 3){
            winningCheck();
            notification.setText(message);
        }
        xTurn = false;
        notification.setText("O, it's your turn.");
        twoIsChosen = true;
        turnCounter++;
    }
if (xTurn == true && threeIsChosen == false && gameOver == false){
        board[0][2] = "X";
        b02.setText(board[0][2]);
        if(turnCounter > 3){
            winningCheck();
            notification.setText(message);
        }
        xTurn = false;
        notification.setText("O, it's your turn.");
        threeIsChosen = true;
        turnCounter++;
    }
if (xTurn == true && oneIsChosen == false && gameOver == false){
        board[0][0] = "X";
        b00.setText(board[0][0]);
        if(turnCounter > 3){
            winningCheck();
            notification.setText(message);
        }
        xTurn = false;
        notification.setText("O, it's your turn.");
        oneIsChosen = true;
        turnCounter++;
    }

I am wanting to compare the contents in array[0][0] with array[0][1] and array[0][2] and they are all the same, they print that the place holder is the winner. When I run the program, the string "X" goes into the array, but I cannot get them to compare to each other. What method is best? I have tried the .equals() method and the .compareto() method but I still can't get anything to work.

Answer 1

对于字符串比较，使用string1.equals(string2)比相等比较好

Answer 2

if (board[0][0].equals(board[0][1]) && board[0][0].equals(board[0][2]))

应该做的伎俩