[英]Deserialize JSON String into DataTable / DataSet using c#
I have following JSON String 我有以下JSON字符串
{
"1":[
{"cityId":93,"cityName":"Tapah","cityCode":"TAP"},
{"cityId":3,"cityName":"Melaka","cityCode":"MLK"},
{"cityId":6,"cityName":"Kota Bharu","cityCode":"KB"},
{"cityId":7,"cityName":"Dungun","cityCode":"DG"}
],
"2":[
{"cityId":77,"cityName":"Grik","cityCode":"GRIK"},
{"cityId":6,"cityName":"Kota Bharu","cityCode":"KB"},
{"cityId":7,"cityName":"Dungun","cityCode":"DG"},
{"cityId":98,"cityName":"Bangan Serai","cityCode":"BS"}
],
"6":[
{"cityId":3,"cityName":"Melaka","cityCode":"MLK"},
{"cityId":82,"cityName":"Teluk Intan","cityCode":"TI"},
{"cityId":7,"cityName":"Dungun","cityCode":"DG"}
]
}
When I using JSON.NET 当我使用JSON.NET时
DataSet obj = JsonConvert.DeserializeObject(responseBody);
数据集obj = JsonConvert.DeserializeObject(responseBody);
I am getting following Table only 我只跟随表
cityId | cityName | cityCode
-----------------------------------
93 Tapah TAP
3 Melaka MLK
6 Kota Bharu KB
7 Dungun DG
I need to like this 我需要这样
from | cityId | cityName | cityCode
-----------------------------------------------
1 93 Tapah TAP
1 3 Melaka MLK
1 6 Kota Bharu KB
1 7 Dungun DG
2 77 Grik GRIK
2 6 Kota Bharu KB
2 7 Dungun DG
2 98 Bangan Serai BS
6 3 Melaka MLK
6 82 Teluk Intan TI
6 7 Dungun DG
The reason for the issue is the incorrect usage of the JsonConvert.DeserializeObject
following should work in this case: 该问题的原因是在这种情况下,
JsonConvert.DeserializeObject
用法不正确:
Define a type / schema with the columns details (as shown in above response) 使用列详细信息定义类型/架构(如上面的响应所示)
public class City
{
public int cityId;
public string cityName;
public string cityCode;
}
Now what you are getting in response body is the type, Json is by default key value pair 现在,您在响应正文中得到的是类型,默认情况下,Json是键值对
Dictionary<object, List<City>>
Now your deserialization code should be: 现在,您的反序列化代码应为:
var obj = JsonConvert.DeserializeObject<Dictionary<object, List<City>>>(responseBody);
obj will be of the type Dictionary<object, List<City>>
obj的类型为
Dictionary<object, List<City>>
Now create the Schema of the Custom Dataset object as follows: 现在,如下创建“自定义数据集”对象的架构:
public class CustomDataset
{
public object from;
public int cityId;
public string cityName;
public string cityCode;
}
Use simple foreach to create the custom dataset from obj type as follows: 使用简单的foreach从obj类型创建自定义数据集,如下所示:
List<CustomDataset> cdList = new List<CustomDataset> ();
foreach(object key in obj.Keys)
{
foreach(City c in obj[key])
{
cdList.Add(key, c.cityId, c.cityName, cityCode);
}
}
cdList of type List<CustomDataset>
wil be your return containing solution you need. 类型为
List<CustomDataset>
cdList将是包含所需解决方案的退货。 Final part using Foreach can be skipped if you use Linq, which would be simple as follows: 如果您使用Linq,则可以跳过使用Foreach的最后一部分,这很简单,如下所示:
List<CustomDataset> cdList =
obj.SelectMany(x => x.Value.Select(y =>
new CustomDataset
{
from = x.Key,
cityId = y.cityId,
cityName = y.cityName,
cityCode = y.cityCode
}
)).ToList();
I suggest de-serializing JSON objects to framework types that are semantically equivalent. 我建议将JSON对象反序列化为在语义上等效的框架类型。 In your case, the JSON is semantically equivalent to
IDictionary<TKey, ICollection<TValue>>>
在您的情况下,JSON在语义上等效于
IDictionary<TKey, ICollection<TValue>>>
IDictionary<int, ICollection<City>> cities;
cities = JsonConvert.DeserializeObject<IDictionary<int, ICollection<City>>>(responseBody);
Then, do the DataSet
conversion yourself instead of relying on reflection. 然后,执行
DataSet
转换自己而不是依靠反射。
var dataSet = new DataSet();
var dataTable = dataSet.Tables.Add();
dataTable.Columns.Add("from");
dataTable.Columns.Add("cityId");
dataTable.Columns.Add("cityName");
dataTable.Columns.Add("cityCode");
// foreach KeyValuePair in IDictionary<TKey, ICollection<TValue>>
foreach (var cityGroup in cities)
{
// foreach TValue in ICollection<TValue>
foreach (var city in cityGroup.Value)
{
dataTable.LoadDataRow(
new object[]
{
cityGroup.Key,
city.cityId,
city.cityName,
city.cityCode
},
LoadOption.PreserveChanges);
}
}
For TValue
, I used a simple data contract class. 对于
TValue
,我使用了一个简单的数据协定类。
public class City
{
public int cityId;
public string cityName;
public string cityCode;
}
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