[英]Splitting an array of strings to an array of floats in JavaScript
I am trying to split an array of strings, called 'vertices' and store it as an array of floats. 我试图拆分一个字符串数组,称为“顶点”并将其存储为浮点数组。
Currently the array of strings contains three elemets: ["0 1 0", "1 -1 0", '-1 -1 0"]
目前,字符串数组包含三个元素:
["0 1 0", "1 -1 0", '-1 -1 0"]
What I need is an array of floats containing all these digits as individual elements: [0, 1, 0, 1, -1, 0, -1, -1, 0]
我需要的是一个包含所有这些数字作为单个元素的浮点数组:
[0, 1, 0, 1, -1, 0, -1, -1, 0]
I used the split() function as follows: 我使用了split()函数,如下所示:
for(y = 0; y < vertices.length; y++)
{
vertices[y] = vertices[y].split(" ");
}
...which gives me what looks to be what I am after except it is still made up of three arrays of strings. ...它给了我看起来像我所追求的东西,除了它仍然由三个字符串数组组成。
How might I use parseFloat() with split() to ensure all elements are separate and of type float? 我如何将split()与parseFloat()一起使用以确保所有元素都是单独的并且类型为float?
You can use Array.prototype.reduce
method for this: 您可以使用
Array.prototype.reduce
方法:
var result = ["0 1 0", "1 -1 0", "-1 -1 0"].reduce(function(prev, curr) { return prev.concat(curr.split(' ').map(Number)); }, []); alert(result); // [0, 1, 0, 1, -1, 0, -1, -1, 0]
Instead of .map(Number)
you can use .map(parseFloat)
of course if you need. 如果需要,您可以使用
.map(parseFloat)
代替.map(Number)
。
Or even shorter: 甚至更短:
var result = ["0 1 0", "1 -1 0", "-1 -1 0"].join(' ').split(' ').map(Number);
You could do something like this. 你可以这样做。
var res = [] for (var y = 0; y < vertices.length; y++) { var temp = vertices[y].split(" "); for (var i = 0; i < temp.length; i++) { res.push(parseFloat(temp[i])); } }
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