将字符串拆分为浮点数和字符数组

Question

We are working with a string that can contain integers, floats and characters.

Example:

.12A1.3B.5CD

I want to take that string and turn it into an array of numbers and characters that looks like

[.12,A,1.3,B,.5,C,0,D]

(when there is no number in front of the letter, it is assumed to be a 0)

I have tried different regex combinations and can't get any to work like:

str.match(/[a-zA-Z]+?[0-9]*\.?[0-9]+/g)

but it gives me the result of:

["12", "A", "1", "3", "B", "5", "CD"]

chopping off the decimal point and not separating the "D" to "0,D"

Again the desired result is [.12,A,1.3,B,.5,C,0,D].

Any guesses?

Answer 1

You could replace the missing zeros and match the parts. Later map the value after checking for number or string.

 var string ='.12A1.3B.5CD', array = string .replace(/((^|[az])(?=\\.))|([az](?=[az]))/gi, '$&0') .match(/[.0-9]+|[az]/gi) .map(v => v == +v ? +v : v); console.log(array); 

 .as-console-wrapper { max-height: 100% !important; top: 0; } 

Answer 2

You can add a zero after each letter if it is followed by another letter and then split on letters:

 var s = ".12A1.3B.5CD"; console.log( s.replace(/([az])(?=[az])/gi, "$1"+"0").split(/([az])/i).filter(x => x != "") ) 

Answer 3

With String.match() , Array.reduce() and isNaN() functions:

 var s = '.12A1.3B.5CD', prev, result = s.match(/(\\d*\\.)?\\d+|[a-zA-Z]/g).reduce(function(a, v){ v = +v || v; if (a.length > 1 && +v !== v && isNaN(prev)) a.push(0); a.push(v); prev = v; return a; }, []); console.log(result) 

"Speed" comparison:

Answer 4

This should do the trick:

str.match(\\([a-zA-Z]|[0-9]*\\.?[0-9]+)\\g)

then using javascript you should insert a 0 into the array between consecutive letters.

A good website to check out regex's: https://regex101.com/r/vhnv2M/1