[英]Mysql select distinct id's and select first row only
This is my table. 这是我的桌子。 I want to select distinct 'bill_no' with only first related row.
我想选择与第一个相关行不同的'bill_no'。
+--------------+--------------+-------+------------+
| id | bill_no | product_name | tax | total |
+--------------+-------+------+-------+------------+
| 1 | 12 | Hairgel | 10 | 241 |
| 2 | 12 | Spiker gel | 10 | 300 |
| 3 | 13 | Wokzem amba | 12 | 450 |
| 4 | 13 | test prod | 1 | 145 |
| 5 | 14 | wokk | 3 | 55 |
| 6 | 14 | Kamer hyp | 11 | 46 |
| 7 | 15 | Xyombokx | 2 | 220 |
+--------------+-------+------+-------+------------+
I want data to be displayed like the below table having only distinct "bill_no" - 我希望数据显示如下表只有明显的“bill_no” -
Output- 输出-
+--------------+--------------+-------+------------+
| id | bill_no | product_name | tax | total |
+--------------+-------+------+-------+------------+
| 1 | 12 | Hairgel | 10 | 241 |
| 3 | 13 | Wokzem amba | 12 | 450 |
| 5 | 14 | wokk | 3 | 55 |
| 7 | 15 | Xyombokx | 2 | 220 |
+--------------+-------+------+-------+------------+
使用group by
select * from youtable group by bill_no
select t1.*
from your_table t1
join
(
select min(id) as id
from your_table
group by bill_no
) t2 on t1.id = t2.id
您可以使用GROUP BY子句.GROUP BY子句始终按cloumn名称返回具有相关组的第一行。
SELECT * FROM `table_1` group by `bill_no`
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