Mysql选择不同的值和最后一行

Question

Very simple.

msg_id    msisdn           message 
----------------------------------   
1000      661000           text1   
1001      661002           text2   
1002      661004           text3   
1003      661002           text4   
1004      661002           text5     
1005      661002           text6  

I need to get distinct msisdn values ordered from newest to oldest and all values in that last row. Please understand that there are more coluns in the real query so I need to get the distinct msisdn's - but also ALL DATA from last row with that msisdn.

msisdn     msg_id    message   
----------------------------- 
661002     1005      text6   
661004     1002      text3   
661000     1000      text1     

Thanks!

Just to be clear. I started with:

select distinct(msisdn), max(msg_id) from table group by msisdn

However pulling all info about max(msg_id) is the problem... I need that whole row in the query, not just msg_id...

Hope it's all clearer now.

Answer 1

You can use a derived table containing the max msg_id per msisdn , then join to this table to get the rest of the columns:

select t1.*
from mytable as t1
inner join (
   select msisdn, max(msg_id) as last_id
   from mytable
   group by msisdn
) as t2 on t1.msisdn = t2.msisdn and t1.msg_id = t2.last_id

Answer 2

select msisdn,msg_id,max(message)
from table1
group by msg_id,msisdn
order by msg_id desc