前缀为mutable.LinkedList，无需在Scala中复制

Question

I need to build up a list very quickly. My idea was to use a mutable.LinkedList and grow by prepending. However I found only the operator +: for prepending and it produces a copy of the list, which is surprising, given that the list is mutable.

Is there a way to prepend and modify the list in place?

Answer 1

I think this is how you are supposed to use it, from a quick glance:

val newList = new LinkedList(newElem, existingList)

Note though that it is deprecated in Scala 2.11 and might get removed in the future.