[英]Using NSUInteger Input to insertObject:___ atIndex:___
I'm trying to create a simple commandline tic-tac-toe game using an NSMutableArray. 我正在尝试使用NSMutableArray创建一个简单的命令行井字游戏。
Created a class called "Board" with the method "getPosition" (I'm assuming this is the best way to get a user input) I'm asking for position, then casting from int to NSUInteger) 使用方法“ getPosition”创建了一个名为“ Board”的类(我假设这是获取用户输入的最佳方法),我要求位置,然后从int转换为NSUInteger
#import "Board.h"
@implementation Board
-(void)getPosition;
{
int enteredPosition;
scanf("%i", &enteredPosition);
NSUInteger nsEnteredPosition = (NSUInteger ) enteredPosition;
NSLog(@"Position = %lu", (unsigned long)nsEnteredPosition);
}
#import <Foundation/Foundation.h>
#import "Board.h"
int main(int argc, const char * argv[])
{
@autoreleasepool {
NSString *currentPlayer;
NSMutableArray *gameBoard=[[NSMutableArray alloc] initWithCapacity:9];
for(int i; i<=2; i++)
{
if(i %2)
{
currentPlayer=@"X";
}
else
{
currentPlayer=@"O";
}
NSLog(@"Player %@, select an open spot 1 - 9 on the board", currentPlayer);
Board *currentPosition = [[Board alloc] init];
[currentPosition getPosition];
[gameBoard insertObject:currentPlayer atIndex:currentPosition]; //this is where i have a problem
}
As I understand it atIndex requires an NSUInteger parameter, but I'm receiving the error message: 据我了解,atIndex需要NSUInteger参数,但是我收到错误消息:
"Incompatible pointer to integer conversion sending 'Board *_strong" to parameter of type 'NSUInteger' (aka 'unassigned long')
“不兼容的指针,将'Board * _strong'发送给'NSUInteger'类型的参数(也就是'unssigned long')
You're using currentPosition
as your index which is a Board
object. 您使用
currentPosition
作为Board
对象的索引。 Perhaps [currentPosition getPosition]
is supposed to return an NSUInteger
. 也许
[currentPosition getPosition]
应该返回NSUInteger
。 If so, try rewriting the last portion of your code like this: 如果是这样,请尝试像这样重写代码的最后一部分:
Board *theBoard = [[Board alloc] init];
NSUInteger currentPosition = [theBoard getPosition];
[gameBoard insertObject:currentPlayer atIndex:currentPosition]; //this is where i have a problem
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