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在同时安装32位和64位Java时

[英]On installing Java for both 32bit and 64bit

原文 2014-11-21 18:49:51 1 1 java/ path/ install

How do you think set the PATH in Windows 7 64bit to have access to both 32 and 64 bit compilers. 您如何看待在Windows 7 64位系统中设置PATH来访问32位和64位编译器。 I have noteiced that appart from different folders everything such as java.exe , javac.exe , etc. are exactly the same. 我注意到，来自不同文件夹的javac.exe诸如java.exe ， javac.exe等的所有内容都完全相同。 I believe the first path in the PATH variable (either with 32bit binaries or the 64bit) will take precedence. 我相信PATH变量中的第一条路径（使用32位二进制文件或64位二进制文件）将具有优先权。

My idea would be to change 64bit compiler's name (java.exe) and class execute program's name (javac.exe) and le't say add 64bit postfix but I am not sure if that would work. 我的想法是更改64位编译器的名称（java.exe）和类执行程序的名称（javac.exe），并且不说添加64bit后缀，但是我不确定这是否可行。 Please advice. 请指教。

Thanks in advance. 提前致谢。

1 个解决方案

java is not the compiler, that's javac. java不是编译器，而是javac。 Also, the compiler generates the same byte-code on 64-bit as it does on 32-bit. 同样，编译器在64位上生成与在32位上相同的字节码。 Assuming you are using pure Java, the only distinction is in the run-time (or JRE) where a 64-bit JRE can address more memory. 假设您使用的是纯Java，唯一的区别是运行时（或JRE），其中64位JRE可以寻址更多的内存。 If you have native code then you must match the settings those libraries were compiled with . 如果您具有本机代码，则必须匹配使用这些库编译的设置。 But, in general, if you are on a 64-bit system with more then 4 gigabytes of memory, only a 64-bit JRE can use the extra memory. 但是，通常，如果您使用的内存超过4 GB的64位系统，则只有64位JRE可以使用额外的内存。