[英]Generic Makefile
I am looking for a generic makefile, which will will build all C++ files in the current directory and all sub-directories (eg, source, test files, gtest, etc) 我正在寻找一个通用的makefile,它将在当前目录和所有子目录(例如源代码,测试文件,gtest等)中构建所有C ++文件。
I have spent a few hours trying out several and finally settled on the solution from make file with source subdirectories . 我花了几个小时尝试了几次,最终确定了源子目录的make文件解决方案。
I need to make three changes to it: 我需要对其进行三处更改:
I have managed to break the makefile, shown below, such that running make gives me 我设法破坏了makefile,如下所示,这样运行make就可以
make: *** No rule to make target
%.cpp=%.o', needed by
myProgram'.make:***没有规则可以使myProgram'成为目标
%.cpp=%.o', needed by
'。 Stop.停止。
How can I make it do those three things? 我该如何做这三件事?
# Recursively get all *.cpp in this directory and any sub-directories
SRC = $(shell find . -name *.cc) $(shell find . -name *.cpp)
INCLUDE_PATHS = -I ../../../ -I gtest -I dummies
#This tells Make that somewhere below, you are going to convert all your source into
#objects
# OBJ = src/main.o src/folder1/func1.o src/folder1/func2.o src/folder2/func3.o
OBJ = $(SRC:%.cc=%.o %.cpp=%.o)
#Tells make your binary is called artifact_name_here and it should be in bin/
BIN = myProgram
# all is the target (you would run make all from the command line). 'all' is dependent
# on $(BIN)
all: $(BIN)
#$(BIN) is dependent on objects
$(BIN): $(OBJ)
g++
#each object file is dependent on its source file, and whenever make needs to create
# an object file, to follow this rule:
%.o: %.cc
g++ -c $(INCLUDE_PATHS) $< -o $@
[Update] Thanks for the help so far. [更新]谢谢您到目前为止的帮助。 To address a few of the comments, I have no control over the mixed *.cc and *.cpp fiel extensions, and I can say that there won't ever be a source file in the directory tree which I do not wish to include in the build.
为了解决一些意见,我无法控制混合的* .cc和* .cpp扩展名,我可以说目录树中永远不会有我不希望包含的源文件。在构建中。
I am still having trouble with the SRC, as no input files are found. 我仍无法使用SRC,因为找不到输入文件。 I guess that I should look more into the find command as it has been a while since I used Linux.
我想我应该更多地考虑find命令,因为自从我使用Linux已经有一段时间了。
Etan points out your problem. 伊坦指出了您的问题。 But you don't have to perform two replacements, just:
但是您不必执行两次替换,只需:
OBJ := $(addsuffix .o,$(basename $(SRCS)))
And, you should always be using :=
, not =
, for assignment when using the shell
function. 并且,在使用
shell
函数时,应该始终使用:=
而不是=
进行分配。
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