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从数组中删除回车符-Javascript

[英]Removing return carriage from an array - Javascript

I have array as shown below: 我有如下所示的数组:

 ["↵", "Oh", "yeah,", "did", "we", "mention", "it’s", "free?↵"]

Is there a way I can remove that ↵ from the string and from the array? 有没有一种方法可以从字符串和数组中删除该??
I tried 我试过了

str.replace(/(\r\n|\n|\r)/gm,"");

This didn't help. 这没有帮助。

You can clean up your array from empty strings using String.prototype.trim combined with Array.prototype.filter to remove falsy values. 您可以将String.prototype.trimArray.prototype.filter结合使用以清除虚假值,从而从空字符串中清除数组。 For example: 例如:

 var arr = ["\\n", "", "Oh", "yeah,", "did", "we", "mention", "it's", "free?\\n"] // check array before alert(JSON.stringify(arr)); arr = arr.map(function(el) { return el.trim(); }).filter(Boolean); // after cleaning up alert(JSON.stringify(arr)); 

Simply split your string on /\\s+/ , then you don't need to perform this action anymore. 只需在/\\s+/上分割字符串,就不再需要执行此操作。

var str='\nOh yeah, did we mention it’s free?\n';
var arr=str.split(/\s+/);

Note: you might want to trim \\s+ from the beginning and end of the string fist. 注意:您可能需要从字符串拳头的开始和结尾处修剪\\s+ (Older) Browsers that do not support trim() can use: (较早的)不支持trim() )的浏览器可以使用:

arr=str.replace(/^\s+|\s+$/g, '').split(/\s+/);

Strictly answering your question how to remove 'carriage returns' from strings in an array: 严格回答您的问题,如何从数组中的字符串中删除“回车符”:

// you have:
var str= '\nOh yeah, did we mention it’s free?\n';
var arr= str.split(' ');

// no function needed, a simple loop will suffice:
for(var L=arr.length; L--; arr[L]=arr[L].replace(/[\n\r]/g, ''));

Note that (as can already be seen in your example as array-item 0) you might end up with some empty strings (not undefined) in your array. 请注意(在您的示例中已经以array-item 0看到),您可能最终在数组中添加了一些空字符串(不是未定义)。

Try this: 尝试这个:

function removeReturn(ary){
  var b = [], a = [];
  for(var i=0,l=ary.length; i<l; i++){
    var s = ary[i].split('');
    for(var n=0,c=s.length; n<c; n++){
      if(s[n] === '\u021B5')s[n] = '';
    }
    b.push(s.join(''));
  }
  for(var i=0,l=b.length; i<l; i++){
    var x = b[i];
    if(x !== '')a.push(x);
  }
  return a;
}

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