Javascript从2个数组中返回数组，删除重复项

Question

Searched and tried and no luck so far.

var newUsers = [{name: 'rich', id: 25}, {name: 'lauren', id: 35}, {name: 'dave', id: 28} ]

var likedUsers = [{name: 'derek', id: 39}, {name: 'rich', id: 25}, {name: 'brian', id: 38} ]

What I want returned is:

var leftUsers = [{name: 'lauren', id: 35}, {name: 'dave', id: 28} ]

basically without the rich object as this is a duplicate. I only care about the id key.

I have tried:

newUsers.forEach((nUser) => {
    likedUsers.forEach((lUser) => {
        if (nUser.id !== lUser.id){
            leftUsers.push(nUser)
        }
    })
})

but obviously this won't work as this will just add them all as soon as they don't match.

if possible would like an es6 solution using forEach/map/filter

thanks

Answer 1

With array.prototype.filter to filter out items that exists in likedUsers and array.prototype.findIndex to check the existence, it should be:

 var newUsers = [{name: 'rich', id: 25}, {name: 'lauren', id: 35}, {name: 'dave', id: 28} ]; var likedUsers = [{name: 'derek', id: 39}, {name: 'rich', id: 25}, {name: 'brian', id: 38} ]; var leftUsers = newUsers.filter(u => likedUsers.findIndex(lu => lu.id === u.id) === -1); console.log(leftUsers); 

Answer 2

You can do this with filter() and some() methods.

 var newUsers = [{name: 'rich', id: 25}, {name: 'lauren', id: 35}, {name: 'dave', id: 28} ] var likedUsers = [{name: 'derek', id: 39}, {name: 'rich', id: 25}, {name: 'brian', id: 38} ] const result = newUsers.filter(e => !likedUsers.some(a => a.id == e.id)); console.log(result) 

Answer 3

 var newUsers = [{name: 'rich', id: 25}, {name: 'lauren', id: 35}, {name: 'dave', id: 28} ]; var likedUsers = [{name: 'derek', id: 39}, {name: 'rich', id: 25}, {name: 'brian', id: 38} ]; var leftusers = newUsers.filter( item => !likedUsers.find(item2 => item.id == item2.id)); console.log(leftusers); 

Answer 4

You can create a Set of ids that are found in likedUsers , and filter the newUsers by checking if an id is in the Set:

 const newUsers = [{name: 'rich', id: 25}, {name: 'lauren', id: 35}, {name: 'dave', id: 28} ] const likedUsers = [{name: 'derek', id: 39}, {name: 'rich', id: 25}, {name: 'brian', id: 38} ] const result = newUsers.filter(function({ id }) { return !this.has(id) // take all users which ids is not found in the set }, new Set(likedUsers.map(({ id }) => id))) // create a set of ids in likedUsers and assign to this console.log(result)