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在SQL中以下查询有什么问题

[英]What is wrong in following query in sql

SELECT jobs.id,jobs.title, jobs.budget, jobs.views_count, jobs.is_active, count(job_applications.id) as count
    FROM jobs 
    LEFT JOIN job_applications ON job_applications.job_id = jobs.id WHERE jobs.user_id ='.$id.'' AND jobs.title=''.$title.' group by jobs.id

This query give error: 该查询给出错误:

syntax error, unexpected '=', expecting ',' or ';' 语法错误,意外的'=',期望为','或';'

The problem is with PHP, not with SQL. 问题出在PHP,而不是SQL。

You have messed up with single quotes. 您搞砸了单引号。

Updated query: 更新的查询:

$sql = "SELECT jobs.id,jobs.title, jobs.budget, jobs.views_count, jobs.is_active, count(job_applications.id) as count
        FROM jobs 
        LEFT JOIN job_applications ON job_applications.job_id = jobs.id WHERE jobs.user_id ='$id' AND jobs.title='$title' group by jobs.id";

try like this 这样尝试

$your_query = "SELECT jobs.id,jobs.title, jobs.budget, jobs.views_count, jobs.is_active, count(job_applications.id) as count FROM jobs 
    LEFT JOIN job_applications ON job_applications.job_id = jobs.id WHERE jobs.user_id =".$id." AND jobs.title='".$title."' group by jobs.id";

Watch your quotes. 注意报价。 Here is your query fixed without double use of quotes: 这是固定的查询,没有重复使用引号:

$query = 'SELECT 
    jobs.id,
    jobs.title, 
    jobs.budget, 
    jobs.views_count, 
    jobs.is_active, 
    count(job_applications.id) as count
    FROM jobs 
LEFT JOIN job_applications ON job_applications.job_id = jobs.id 
WHERE 
    jobs.user_id ='.$id.' 
    AND jobs.title='.$title.' 
group by jobs.id';

If $title pertains to a string, use the following, as pointed out by @daiscog: 如果$title与字符串有关,请使用@daiscog指出的以下内容:

$query = 'SELECT 
    jobs.id,
    jobs.title, 
    jobs.budget, 
    jobs.views_count, 
    jobs.is_active, 
    count(job_applications.id) as count
    FROM jobs 
LEFT JOIN job_applications ON job_applications.job_id = jobs.id 
WHERE 
    jobs.user_id ='.$id.' 
    AND jobs.title=\''.$title.'\' 
group by jobs.id';

Change this 改变这个

jobs.user_id ='.$id.'' AND jobs.title=''.$title.'

to

jobs.user_id ='.$id.' AND jobs.title='.$title.'

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