[英]Configure grunt.js to minify files one by one in bower folder
I have the dependencies of the application in bower_components , some of the dependencies don't have a minified version so I'd like to create a task creates a minified copy of the file version in the same place where the file is located like: 我在bower_components中具有应用程序的依赖项 ,其中一些依赖项没有缩小版本,因此我想创建一个任务,在文件所在的相同位置创建文件版本的缩小副本,例如:
This is my grunt Config so far: 到目前为止,这是我最讨厌的配置:
uglify: {
dev: {
files:[
{
expand: true,
src: 'bower_components/modernizr/modernizr.js',
dest: '/',
ext:'.min.js'
}, {
expand: true,
src: 'bower_components/angular-facebook/lin/angular-facebook.js',
dest: '/',
ext: '.min.js'
}]
},
main: {
src: 'temp/app.min.js',
dest:'dist/app.min.js'
}
}
the Grunt task says that copied modernizr to it's own folder but when I look at it, the file is not there and after the first file Grunt passes to the next task and ignores the 'second' file in the array. Grunt任务说复制了modernizr到它自己的文件夹,但是当我查看它时,文件不存在,在第一个文件Grunt传递到下一个任务之后,它忽略了数组中的“第二个”文件。
I was just testing this obviously I'd like to implement a way that grunt scan all the dependencies in bower_components automatically. 我只是在测试这一点,显然我想实现一种方法, 可以自动扫描 bower_components中的 所有 依赖 项 。
btw, I don't mind to change the task to any other library. 顺便说一句,我不介意将任务更改为任何其他库。
the /
in your dest
-option means the root path (were your gruntfile resides). dest
-option中的/
表示根路径(您的gruntfile位于其中)。 just delete the dest
-option or put an empty string there. 只需删除dest
-option或在其中放置一个空字符串即可。
important: this just works with the expand
-option set! 重要:这仅适用于expand
-option设置!
{
expand: true,
src: 'bower_components/modernizr/modernizr.js',
ext:'.min.js'
}
Edit: 编辑:
for scanning all folders an minimizing all js files do it like this (note the second argument in src to not minify files which are already minified): 要扫描所有文件夹,请最小化所有js文件,方法是这样的(请注意src中的第二个参数不缩小已经缩小的文件):
{
expand: true,
src: ['bower_components/**/*.js', '!bower_components/**/*.min.js'],
ext:'.min.js'
}
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