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需要一些PHP帮助

[英]Need some PHP assistance

how do i tell this php code that, when there's not a ?page=randompage in the url, it will trow the active to index.php automatically? 我如何告诉这个php代码,当URL中没有?page = randompage时,它将自动将活动代码拖到index.php吗?

<?php
$query = "SELECT pagename, pagetitle FROM pages LIMIT 8"; 
$result = $mysqli->query($query); 
echo "<ul>";
while ($row = $result->fetch_array(MYSQLI_ASSOC)){ 
  echo "<li><a href=\"?page=".$row["pagename"]."\""; 
  if ($_GET['page'] == $row['pagename']) { 
  echo " class=\"active\""; } echo "> ".$row["pagetitle"]." </a></li>";
}
echo "</ul>";
?>

It's beacuse whenever my url looks like this http://localhost/greencph/ it shows a php error, because it does not know which site it is on, it works perfect as long as the url looks like this: http://localhost/greencph/?page=index.php a detailed explanation on how to fix this problem would be appreciated! 这是因为每当我的URL看起来像这样的http://localhost/greencph/它就会显示php错误,因为它不知道它在哪个站点上,因此只要URL看起来像这样,它就可以完美运行: http://localhost/greencph/?page=index.php有关如何解决此问题的详细说明,将不胜感激!

Please remember i'm a idiot, explain to me so i understand it. 请记住我是个白痴,向我解释,以便我理解。 xD 的xD

The error is coming because, every time the value of $_GET is not getting set. 因为每次没有设置$_GET的值,都会出现错误。

So, to deal with it, 因此,要处理它,

get the value of $_GET['page'] in a variable. 在变量中获取$_GET['page']的值。

So that, if we do not get $_GET , we will assign it a default value, that is index page. 因此,如果没有得到$_GET ,我们将为其分配一个默认值,即索引页。

$page = ! empty($_GET['page']) ? $_GET['page'] : 'index'; // set default value.

And change this line: 并更改此行:

if ($page == $row['pagename']) {

So, the final modified code should be: 因此,最终的修改后的代码应为:

<?php
$query = "SELECT pagename, pagetitle FROM pages LIMIT 8";
$result = $mysqli->query($query);
$page = ! empty($_GET['page']) ? $_GET['page'] : 'index';
echo '<ul>';
while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
    $class = '';
    if ($page == $row['pagename']) {
        $class =  'active';
    }
    echo '<li><a href="?page='.$row["pagename"].'" class="'.$class.'">' . $row["pagetitle"].' </a></li>';
}
echo "</ul>";
?>

Use the $_GET array: 使用$_GET数组:

<?php
   if(isset($_GET['page'])) {
       // Your code
       ...
   }
?>

Problem is in this line 问题在这条线

if ($_GET['page'] == $row['pagename']) {

You're not checking whether the index 'page' even exists. 您无需检查索引“页面”是否存在。 So, when you try to load the page without any GET parameters $_GET['page'] won't be even set and you'll get an error for accessing unset element. 因此,当您尝试在没有任何GET参数的情况下加载页面时,甚至都不会设置$_GET['page']并且在访问unset元素时会出现错误。

To fix this simply check 要解决此问题,只需检查

if(isset($_GET['page']) {
    ...your code...
}

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