[英]Ajax not working using jquery url post method
I am trying to make a stepy-form for my project. 我正在尝试为我的项目制作表格。 What I want to do is I want to submit all my data step by step in stepy-form so I used an AJAX request for this purpose, but When I am trying to save it it's not working.
我想要做的是我要逐步以步进形式提交所有数据,因此我为此目的使用了AJAX请求,但是当我尝试保存它时却无法正常工作。 So I used
noConflict
Method to avoid jQuery conflicts but I still have the same problem. 因此,我使用
noConflict
方法来避免jQuery冲突,但是我仍然noConflict
相同的问题。 I am using adminEX template And Not getting any error message. 我正在使用adminEX模板并且未收到任何错误消息。 So can anyone help me?
有人可以帮我吗?
<script src="ajax/jquery.min.js"></script>
<script>
$.noConflict();
Jquery(document).ready(function(){
$('#stepy_form').click(function(){
$.ajax({
type: 'POST',
url: 'ajax/insert_all.php',
data: {
txtVehicleNo: txtVehicleNo,
SltType: SltType,
txtPANNumber: txtPANNumber,
txtManufacture: txtManufacture,
txtModel: txtModel,
txtEngineNumber: txtEngineNumber,
txtChassisNumber: txtChassisNumber,
txtOwnerName: txtOwnerName,
txtUnlaidenWt: txtUnlaidenWt,
txtGVW: txtGVW
// qid: 'form1'
},
//alert('hello');
//async: true,
//cache: false,
success: function(result) {
alert('SUCCESS');
//$('#target').html(result);
}
});
});
});
</script>
And this one is the URL ,insert_all.php 这是URL,insert_all.php
$qid = $_POST['qid'];
echo $qid;
You are not using 'no conflict' with jquery and accessing it using $
. 您没有在jquery中使用'no冲突',而是在
$
访问它。 Change $ with jQuery like this 像这样用jQuery更改$
$.noConflict();
jQuery(document).ready(function(){
jQuery('#stepy_form').click(function(){
jQuery.ajax({
type: 'POST',
url: 'ajax/insert_all.php',
data: {
txtVehicleNo: txtVehicleNo,
SltType: SltType,
txtPANNumber: txtPANNumber,
txtManufacture: txtManufacture,
txtModel: txtModel,
txtEngineNumber: txtEngineNumber,
txtChassisNumber: txtChassisNumber,
txtOwnerName: txtOwnerName,
txtUnlaidenWt: txtUnlaidenWt,
txtGVW: txtGVW
},
success: function(result) {
alert('SUCCESS');
//$('#target').html(result);
}
});
});
});
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