如何使用jQuery Ajax执行发布方法

Question

I'm trying to make a simple post method using jquery ajax. 我正在尝试使用jquery ajax创建一个简单的post方法。 Whenever I click submit button, Im getting an error:400(Bad request) in my console. 每当我单击提交按钮时，我的控制台中都会出现错误：400（错误请求）。 Im not sure what is the mistake in the code, I will be happy if anyone helps with the issue. 我不确定代码中的错误是什么，如果有人帮助解决该问题，我将非常高兴。 Thank you. 谢谢。

Note: The URL used in the code is a dummy and not a working URL. 注意：代码中使用的URL是虚拟的，而不是有效的URL。

<html>

    <head>
        <link href="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.0.2/css/bootstrap.min.css" rel="stylesheet" type="text/css"
            media="all" />
        <link href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-formhelpers/2.3.0/css/bootstrap-formhelpers.min.css" rel="stylesheet"
            type="text/css" media="all" />
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
        <script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-formhelpers/2.3.0/js/bootstrap-formhelpers.min.js"></script>
        <script type="text/javascript">
            function ok(){
                var thisForm = $(this).closest('form.contactPage');
                var sendData = thisForm.serialize();
                jQuery.ajax({
                 type: "POST",
                // url is dummy and not a working url
                 url: "dummy URL", 
                 data: thisForm.serialize(),
                    data: sendData,
                    success : function(data, textStatus, jqXHR)
                    {

                        console.log(data);
                    },
                    error: function(jqXHR, textStatus, error){
                        console.log(error);
                    }
                })
            }            
        </script>
    </head>

    <body>
        <form name="contactPage" class="form-email">

            <input type="text" class="form-control input-lg input-sm validate-required" id="name" placeholder="Contact Person" />
            <div class="form-group">
                <select class="form-control input-lg bfh-countries wrapper-dropdown-2 validate-required" id="dd" data-country="US"></select>
            </div>
            <input type="text" class="form-control input-lg validate-required" id="contactNum" placeholder="Contact Number" />
            <input type="text" class="form-control input-lg validate-required validate-email" id="email" placeholder="Email Address" />
            <input type="time" class="form-group form-control input-lg validate-required" id="time" placeholder="Time" />
            <input type="submit" class="form-group form-control" value="Contact" onclick="ok()" />
        </form>
    </body>
    </html>

Answer 1

<!DOCTYPE html>
<html>
<head>
 <link href="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.0.2/css/bootstrap.min.css" rel="stylesheet" type="text/css"
            media="all" />
        <link href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-formhelpers/2.3.0/css/bootstrap-formhelpers.min.css" rel="stylesheet"
            type="text/css" media="all" />
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
        <script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-formhelpers/2.3.0/js/bootstrap-formhelpers.min.js"></script>

</head>
<body>
<form name="contactPage" id="contactPage" class="form-email">

            <input type="text" class="form-control input-lg input-sm validate-required" id="name" placeholder="Contact Person" />
            <div class="form-group">
                <select class="form-control input-lg bfh-countries wrapper-dropdown-2 validate-required" id="dd" data-country="US"></select>
            </div>
            <input type="text" class="form-control input-lg validate-required" id="contactNum" placeholder="Contact Number" />
            <input type="text" class="form-control input-lg validate-required validate-email" id="email" placeholder="Email Address" />
            <input type="time" class="form-group form-control input-lg validate-required" id="time" placeholder="Time" />
            <input type="submit" class="form-group form-control" value="Contact"/>
        </form>
<script>
$(document).ready(function(){

     $(function(){
        $("#contactPage").submit(function(event){
            event.preventDefault();
            $.ajax({
                    url:'url.php',
                    type:'POST',
                    data:$(this).serialize(),
                    success:function(result){
                       alert(result);
                    }
            });
        });
    });
});
</script>
</body>
</html>

Answer 2

That URL seems to invalid. 该网址似乎无效。

I suggest you check the URL given. 我建议您检查给出的URL。

Answer 3

The URL provided by you is not valid. 您提供的网址无效。 try again with a valid URL.. 请使用有效的网址再试一次。

如何使用jQuery Ajax执行发布方法

问题描述

3 个解决方案

解决方案1
1 已采纳 2017-03-15 13:08:41

解决方案2
0 2017-03-15 11:25:40

解决方案3
0 2017-03-15 11:31:13

如何使用jQuery Ajax执行发布方法

问题描述

3 个解决方案

解决方案1 1 已采纳 2017-03-15 13:08:41

解决方案2 0 2017-03-15 11:25:40

解决方案3 0 2017-03-15 11:31:13

解决方案1
1 已采纳 2017-03-15 13:08:41

解决方案2
0 2017-03-15 11:25:40

解决方案3
0 2017-03-15 11:31:13