如何使用sed或awk在单行中排列单词？

Question

My file contents:

Google
Facebook
yahoo
cisco
juniper
oracle
firetide
attack

I wanted to convert the above words(column) into a row as shown below:

Google Facebook yahoo cisco juniper oracle firetide attack

NOTE : There should be a single space between each word.

Please suggest me a way to achieve this using sed or awk.

Thanks in advance.

Answer 1

Using shell

If shell solutions are allowable, then try:

$ echo $(cat inputfile) 
Google Facebook yahoo cisco juniper oracle firetide attack

The above should work with any POSIX shell. With bash :

$ echo $(<inputfile) 
Google Facebook yahoo cisco juniper oracle firetide attack

Using sed

If we really must use awk or sed , then here is a sed solution:

$ sed ':a;N;$!ba; s/\n/ /g' inputfile
Google Facebook yahoo cisco juniper oracle firetide attack

The above reads the whole file in ( :a;N;$!ba ) and then replaces all newlines with spaces ( s/\\n/ /g ).

If the input file might contain extra spaces at the beginning for end of a line, we can remove them:

$ sed ':a;N;$!ba; s/[[:space:]]*\n[[:space:]]*/ /g' inputfile
Google Facebook yahoo cisco juniper oracle firetide attack

Answer 2

Using awk

$ awk 'ORS=FS' inputFile
Google Facebook yahoo cisco juniper oracle firetide attack 

OR

Another variation would be

$ awk 1 ORS=' ' input
Google Facebook yahoo cisco juniper oracle firetide attack

Answer 3

Here is another way to do it:

xargs <file
Google Facebook yahoo cisco juniper oracle firetide attack

This also give a newline at the end unlike the awk posted.

Answer 4

使用tr ：

tr '\n' ' ' < File

Answer 5

用awk：

awk '{printf "%s ", $0}' file

Answer 6

sed -n '1h;1!H;${x;s/ *\n */ /gp;}' YourFile

• 用简单的空格替换起始/结束空间和新行（因此将删除任何起始空间）。