[英]R: transform data (factor value as column name)
I have a dataset that I want to transform in to another format: 我有一个数据集,我想转换为另一种格式:
The data looks like this (for privacy issue, I cannot put the original data): 数据看起来像这样(对于隐私问题,我不能把原始数据):
ID1 ID2 Month Value
1 A Jan-03 10
2 B Jan-03 11
1 A Feb-03 12
2 B Feb-03 13
1 A Mar-03 14
2 B Mar-03 15
I want the Month column to be as the column name, and the format looks like this: 我希望Month列作为列名,格式如下所示:
ID1 ID2 Jan-03 Feb-03 Mar-03
1 A 10 12 14
2 B 11 13 16
Thanks! 谢谢!
You could try 你可以试试
df$Month <- factor(df$Month, levels=unique(df$Month))
reshape(df, idvar=c('ID1', 'ID2'), timevar='Month', direction='wide')
# ID1 ID2 Value.Jan-03 Value.Feb-03 Value.Mar-03
#1 1 A 10 12 14
#2 2 B 11 13 15
Or 要么
library(reshape2)
dcast(df, ID1+ID2~Month, value.var='Value')
# ID1 ID2 Jan-03 Feb-03 Mar-03
#1 1 A 10 12 14
#2 2 B 11 13 15
Or 要么
library(tidyr)
spread(df, Month, Value)
# ID1 ID2 Jan-03 Feb-03 Mar-03
#1 1 A 10 12 14
#2 2 B 11 13 15
df <- structure(list(ID1 = c(1L, 2L, 1L, 2L, 1L, 2L), ID2 = c("A",
"B", "A", "B", "A", "B"), Month = c("Jan-03", "Jan-03", "Feb-03",
"Feb-03", "Mar-03", "Mar-03"), Value = 10:15), .Names = c("ID1",
"ID2", "Month", "Value"), class = "data.frame", row.names = c(NA,
-6L))
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