[英]Numpy 2d and possibly N-d indexing by array of tuples
With 1d arrays it's possible to index it by Nd array of integers like this: 使用1d数组,可以通过Nd个整数数组进行索引,如下所示:
>>> rand = np.random.rand(9).astype(np.float32)
>>> rand
array([ 0.69786191, 0.09376735, 0.60141236, 0.35305005, 0.68340319,
0.0746202 , 0.11620298, 0.46607161, 0.90864712], dtype=float32)
>>> u = np.random.randint(0, 9, (2,2))
>>> u
array([[0, 6],
[5, 6]])
>>> rand[u]
array([[ 0.69786191, 0.11620298],
[ 0.0746202 , 0.11620298]], dtype=float32)
But I can't do the same with 2d arrays: 但是我不能对2d数组做同样的事情:
>>> rand2d = np.random.rand(9).astype(np.float32).reshape(3,3)
>>> rand2d
array([[ 0.83248657, 0.75025952, 0.87252802],
[ 0.78049046, 0.92902303, 0.42035589],
[ 0.80461669, 0.49386421, 0.56518084]], dtype=float32)
>>> u = np.random.randint(0, 3, (2,2,2))
>>> u
array([[[2, 2],
[2, 2]],
[[0, 2],
[0, 1]]])
>>> rand2d[u]
array([[[[ 0.80461669, 0.49386421, 0.56518084],
[ 0.80461669, 0.49386421, 0.56518084]],
[[ 0.80461669, 0.49386421, 0.56518084],
[ 0.80461669, 0.49386421, 0.56518084]]],
[[[ 0.83248657, 0.75025952, 0.87252802],
[ 0.80461669, 0.49386421, 0.56518084]],
[[ 0.83248657, 0.75025952, 0.87252802],
[ 0.78049046, 0.92902303, 0.42035589]]]], dtype=float32)
While the result I expected is: 虽然我期望的结果是:
[[rand2d[2, 2], rand2d[2, 2]],
[rand2d[0, 2], rand2d[0, 1]]] ==
[[0.56518084, 0.56518084],
[0.87252802, 0.75025952]]
How can I achieve this without iterating? 我如何不进行迭代就实现这一目标?
Straight from the example in the docs : 直接来自docs中的示例 :
>>>
>>> x
array([[ 0, 1, 2],
[ 3, 4, 5],
[ 6, 7, 8],
[ 9, 10, 11]])
>>>
>>> rows = np.array([[0,0],[3,3]])
>>> columns = np.array([[0,2],[0,2]])
>>> x[rows,columns]
array([[ 0, 2],
[ 9, 11]])
>>>
You can see that it is selecting items at (0,0), (0,2) and (3,0),(3,2). 您可以看到它正在选择(0,0),(0,2)和(3,0),(3,2)的项目。
You can have a look at unravel_index . 您可以看一下unravel_index 。 Not sure if this is exactly what you are after, but it might be useful:
不知道这是否正是您所追求的,但这可能很有用:
import numpy as np
rand2d = np.array([[ 0.83248657, 0.75025952, 0.87252802],
[ 0.78049046, 0.92902303, 0.42035589],
[ 0.80461669, 0.49386421, 0.56518084]], dtype=np.float32)
u = np.random.randint(0, 3, (2,2,2))
print(rand2d[np.unravel_index(u, rand2d.shape)])
Example output is: 示例输出为:
[[[ 0.87252802 0.75025952]
[ 0.83248657 0.75025952]]
[[ 0.87252802 0.87252802]
[ 0.75025952 0.87252802]]]
Thanx wwii. 谢谢第二次世界大战。 My point is indexing an array with matrix of each element coordinates (as example - for per-pixel shift).
我的观点是用每个元素坐标的矩阵对数组进行索引(例如,针对每个像素的移动)。 For my case solution is:
就我而言,解决方案是:
>>> u
array([[[2, 2],
[2, 2]],
[[0, 2],
[0, 1]]])
>>> ux = u.transpose(2,0,1)
>>> ux
array([[[2, 2],
[0, 0]],
[[2, 2],
[2, 1]]])
>>> rand2d[ux[0], ux[1]]
array([[ 0.56518084, 0.56518084],
[ 0.87252802, 0.75025952]], dtype=float32)
Also, here is my solution to get this array of coordinates, operate with it and use it back for indexing: 另外,这是我的解决方案,用于获取此坐标数组,对其进行操作并将其用于索引编制:
>>> ux = np.indices(rand2d.shape)
>>> ux
array([[[0, 0, 0],
[1, 1, 1],
[2, 2, 2]],
[[0, 1, 2],
[0, 1, 2],
[0, 1, 2]]])
>>> u = ux.transpose(1,2,0)
>>> u
array([[[0, 0],
[0, 1],
[0, 2]],
[[1, 0],
[1, 1],
[1, 2]],
[[2, 0],
[2, 1],
[2, 2]]])
>>> u[1,1]-=1
>>> u
array([[[0, 0],
[0, 1],
[0, 2]],
[[1, 0],
[0, 0],
[1, 2]],
[[2, 0],
[2, 1],
[2, 2]]])
>>> ux = u.transpose(2,0,1) #Transpose back
>>> ux
array([[[0, 0, 0],
[1, 0, 1],
[2, 2, 2]],
[[0, 1, 2],
[0, 0, 2],
[0, 1, 2]]])
>>> rand2d[ux[0], ux[1]]
array([[ 0.83248657, 0.75025952, 0.87252802],
[ 0.78049046, 0.83248657, 0.42035589],
[ 0.80461669, 0.49386421, 0.56518084]], dtype=float32)
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