从批处理脚本中的.lnk快捷方式获取源.exe文件名？

Question

I have to extract source filename from .lnk shortcut in batch. The extracted text must be in (program name).(extension) form.

I must admit that I'm a complete laic, when it comes to batch (or any scripting actually), so any help concerning my question is highly appreciated.

Answer 1

You can do it with a wmic query to win32_shortcutfile . Just make sure all your backslashes are backslash-escaped within %filename% .

@echo off
setlocal

:: ensure user supplied a filename with a .lnk extension
if /i "%~x1" neq ".lnk" (
    echo usage: %~nx0 shortcut.lnk
    goto :EOF
)

:: set filename to the fully qualified path + filename
set "filename=%~f1"

:: convert single backslashes to double
set "filename=%filename:\=\\%"

:: get target
for /f "tokens=1* delims==" %%I in ('wmic path win32_shortcutfile where "name='%filename%'" get target /format:list ^| find "="') do (
    echo(%%J
)

What you want ends up in %%J . If you only want the target filename.ext , change that to %%~nxJ . If you want only the drive and path, change it to %%~dpJ . See the last page of help for in a cmd console for more info about variable expansion.