批处理脚本从源文件中读取文件名并将所有出现的路径写入输出文件

Question

I need a batch script that reads a value from a file and searches for it in a directory tree. It should print paths and file name of all the occurrences into an output file. The in put file will have multiple values.

    Directory structure  
    Dir1/DirA/file.txt  
    Dir1/DirA/file1.txt  
    Dir1/DirB/file.txt  
    Dir1/DirA/file2.txt  
    Dir1/DirC/file5.txt  
    Dir1/DirX/file5.txt  


    Source file  
    file.txt  
    file1.txt  
    file2.txt  
    file5.txt  
    file9.txt  

    Desired Output file  

    Dir1/DirA/file.txt  
    Dir1/DirB/file.txt  
    file.txt Count 2  

    Dir1/DirA/file1.txt  
    file1.txt Count 1  

    Dir1/DirA/file2.txt  
    file1.txt Count 1  

    Dir1/DirC/file5.txt  
    Dir1/DirX/file5.txt  
    file5.txt Count 2  

    file9.txt Count 0  

Answer 1

There are two critical components in this solution: one get the path and the file name together, the second one to test if the file exist.

1. Use the modify to get path info http://technogadge.com/how-to-clear-vivaldi-browser-history-cache-cookies/

2. Use the exist keyword in if statement to detect if the file exist

   if exist filepath (

   echo "got it"

   )