正则表达式在PHP中使用单词之后和字符之前的所有内容

Question

I'm trying to get regex to work to take everything after "test" and before "@" in an email so "test-12345@example.com would become 12345.

I've got this far to get it to return everything before the "@" symbol. (Working in PHP)

!(\d+)@!

Answer 1

Either you can use capturing groups and use the regex

test-(\d+)@

and use $1 or use lookaheads and behinds like (?<=test-)\\d+(?=@) which will just match 12345

Answer 2

(?<=test-)[^@]+

You can try this.No need to use groups.See demo.

https://regex101.com/r/eZ0yP4/28

Answer 3

You want everything between test and @ so don't use \\d .

$myRegexPattern = '#test([^@])*@#Ui';
preg_match ($myRegexPattern, $input, $matches);
$whatYouNeed = $matches[1];

Answer 4

Try this

$input = 'test-12345@example.com';
$regexPattern =  '/^test(.*?)\@/';
preg_match ($regexPattern, $input, $matches);
$whatYouNeed = $matches[1];
var_dump($whatYouNeed);