PHP Regex-查找单词并获取所有字符

Question

Im trying to find a regex pattern that matches a string, and return everything after that string until '/'. I currently have:

'/forums\/topic\/\s*([^\/]*)/u'

but this returns everything including 'forums/topic/'

Example: string:

equest lorem ipsum dawhdk scripts. Problem: a href="__;_base_url_j;p_i;oj/index.php?/forums/topic/975-example-maps-to-local-rating/" then does something,

I only need "975-example-maps-to-local-rating"

Answer 1

$pat = '=forums/topic/\s*([^/]*)=u';
$str = 'equest lorem ipsum dawhdk scripts. Problem: a href="__;_base_url_j;p_i;oj/index.php?/forums/topic/975-example-maps-to-local-rating/" then does something,';

preg_match($pat, $str, $match);

var_dump($match);

Output:

array(2) {
  [0]=>
  string(45) "forums/topic/975-example-maps-to-local-rating"
  [1]=>
  string(32) "975-example-maps-to-local-rating"
}

Answer 2

You can use a regex like this:

.*/(.*)/

Working demo

Php code

$re = '~.*/(.*)/~';
$str = 'equest lorem ipsum dawhdk scripts. Problem: a href="__;_base_url_j;p_i;oj/index.php?/forums/topic/975-example-maps-to-local-rating/" then does something, ';

preg_match_all($re, $str, $matches);

// Print the entire match result
var_dump($matches);