在bash中查找并替换相同的字符串

Question

I have a string with some words in them, example a=1 b=2 c=3 a=50 . Now I want to parse this and create another string a=50 b=2 c=3 which is essentially the same as above except that if the same phrase before the = is encountered for the second time the first one is over written with the latest one, so in the end there are only unique phrases on the left of = . Here is what I got till now:

a="a=1 b=2 c=3 a=50"
o=()

for i in $a
do
    reg=${i%=*}
    if [[ ${o[*]} == *"$reg"* ]]
    then
        o=$(echo ${o[*]} | sed -e "s/\$reg=\S/\$i")
    else
        o+=( $i )
    fi
done

What am I doing wrong here?

Answer 1

I'd take an entirely different approach, not based on regular expressions or string rewriting.

declare -A values=( )              # Initialize an associative array ("hash", "map")
while IFS= read -r -d' ' word; do  # iterate over input words, separated by spaces
  if [[ $word = *=* ]]; then       # ignore any word that doesn't have an "=" in it
    values[${word%%=*}]=${word#*=} # add everything before the "=" as a key...
  fi                               # ...with everything after the "=" as a value
done

for key in "${!values[@]}"; do     # Then iterate over keys we found
  value="${values[$key]}"          # ...extract the values for each...
  printf '%s=%s ' "$key" "$value"  # ...and print the pairs.
done
echo                               # When done iterating, print a newline.

Because the words are being processed first-to-last through the string, updates take effect before the print loop is reached.

Answer 2

Using awk

$ awk -F= -v RS=" |\n" '{a[$1]=$2} END{for (k in a) printf "%s=%s ",k,a[k]}' <<<"a=1 b=2 c=3 a=50"
a=50 b=2 c=3

How it works:

• -F=

  Set the field separator to be an equal sign.

• -v RS=" |\\n"

  Set the record separator to be either a space or a newline.

• a[$1]=$2

  Update associative array a with the latest value.

• END{for (k in a) printf "%s=%s ",k,a[k]}

  In no particular order, print out the final values.

Using bash

Like Charles Duffy's approach, this uses read -d" " to parse the string. This approach, however, uses IFS="=" to separate names and values.

Two loops are required. The first gathers the values. The second reassembles the updated values in the original order:

a="a=1 b=2 c=3 a=50"
declare -A b
while IFS== read -d" " name value
do
    b["$name"]="$value"
done <<<"$a "

declare -A seen
while IFS== read -d" " name value
do
    [ "${seen[$name]}" ] || o="$o $name=${b["$name"]}"
    seen[$name]=1
done <<<"$a "
echo "$o"

Answer 3

Easily done with perl:

echo "a=1 b=2 c=3 a=50" \
  | sed "s/ /\n/g" \
  | perl -e '
my %hash = ();
while(<>){
  $line = $_;
  if($line =~ m/(\S+)=(\S+)/) {
    $hash{$1} = $2;
  }
}
for $key (sort keys %hash) {
  print "$key=$hash{$key}\n";
}'

...or, all on one line:

echo "a=1 b=2 c=3 a=50" | sed "s/ /\n/g" | perl -e 'my %hash = (); while(<>){ $line = $_; if($line =~ m/(\S+)=(\S+)/) { $hash{$1} = $2; } } for $key (sort keys %hash) { print "$key=$hash{$key}\n"; }'