如何防止在提交按钮单击时刷新页面

Question

i have form with one input and one submit button.

<form method='POST' action='' enctype='multipart/form-data' id="form_search">
<input type='hidden' name="action" id="form_1" value='1' />
</span><input id="query" type="text" name="mol" value="">
<input type='submit' value='Search' name="Search" id="Search" />

on form submission form input data goes to php below code

if (isset($_POST['Search'])) {
$_SESSION["query"] = $_POST["mol"];
$_SESSION["action"] = $_POST["action"];
}

i want to avoid page refresh on form submission. i tried e.preventDefault() and return false; methods in my java script but not working(this methods helping me from page refresh but does not allowing me to send data to php code)

please help me out of this problem, please suggest working ajax code for this problem.

Answer 1

Page refresh will delete you previous data so to reserve it you can use $.post() or $.ajax()

You can prevent page refreshing by adding one of these two things in event handler function

for pure js

 return false;

for jquery you can use

e.preventDefault(); // e is passed to handler

Your complete code will be something like

using $.post() in js

function checkfunction(obj){
$.post("your_url.php",$(obj).serialize(),function(data){
 alert("success");
 });
 return false;
 }

html

<input type='submit' onclick="return checkfunction(this)" />

or same effect with onsubmit

<form  onsubmit="return checkfunction(this)" method="post">

Answer 2

Without ajax you can simply add the checked attribute in PHP. So for example if your radio group has the name radio and one has value a , the other b :

<?php
$a_checked = $_POST['radio'] === 'a';
$b_checked = $_POST['radio'] === 'b';
?>

<input type="radio" name="radio" value="a"<?=($a_checked ? ' checked' : '')?>></input>
<input type="radio" name="radio" value="b"<?=($b_checked ? ' checked' : '')?>></input>

So when a user submits the form and you display it again, it will be like the user submitted it even the page refreshes.

Answer 3

<input type="radio" name="rbutton" id="r1">R1
<input type="radio" name="rbutton" id="r2">R2
<input type="button" id="go" value="SUBMIT" />
<div id="result"></div>

<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type="text/javascript">

$(document).ready(function(){
    $('#go').click(function(){
        var val1 = $('input:radio[name=rbutton]:checked').val();
        var datastring = "partialName="+val1;
        $.ajax({
            url: "search.php",
            type: "POST",
            data: datastring,
            success: function(data)
            {
                $("#result").html(data);
            }
        });
    });
});
</script>