Python正则表达式，条件搜索

Question

I am trying to split this sentence

"Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot " \
"for it. Did he mind? Adam Jones Jr. thinks he didn't. In any case, this " \
"isn't true... Well, with a probability of .9 it isn't."

Into list of below.

Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot for it.
Did he mind?
Adam Jones Jr. thinks he didn't.
In any case, this isn't true...
Well, with a probability of .9 it isn't.

Code:

print re.findall('([A-Z]+[^.].*?[a-z.][.?!] )[^a-z]',text)

Output:

['Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid
 a lot for it. ', "Adam Jones Jr. thinks he didn't. "]

K gud, but it missed some, is there a way to tell Python since last [^az] isn't part of my group, pls continue searching from there.

EDIT:

This was achieved through forward look ahead regex as mentioned by @sputnick.

print re.findall('([A-Z]+[^.].*?[a-z.][.?!] )(?=[^a-z])',text)

Output:

['Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid
 a lot for it. ', 'Did he mind? ', "Adam Jones Jr. thinks he didn't. "
, "In any case, this isn't true... "]

But we still need the last sentence. Any ideas?

Answer 1

Try this :

print re.findall('([A-Z]+[^.].*?[a-z.][.?!] )(?=[^a-z])',text)

using positive look-ahead regex technique, check http://www.regular-expressions.info/lookaround.html

Answer 2

(.+?)(?<=(?<![A-Z][a-z])(?<![a-z]\.[a-z])(?:\.|\?)(?=\s|$))

Try this.See demo.Grab the capture or groups.Use re.findall .

https://regex101.com/r/gQ3kS4/45

Answer 3

Finally

 print re.findall('[A-Z]+[^.].*?[a-z.][.?!] (?=[^a-z])|.*.$',text)

Above works perfect as needed. Includes the last sentence. But I have no idea why |.*.$ worked pls help me understand.

Output:

['Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid
 a lot for it. ', 'Did he mind? ', "Adam Jones Jr. thinks he didn't. "
, "In any case, this isn't true... ", "Well, with a probability of .9 
it isn't."]