Python 条件正则表达式

Question

My program is given an object with parameters, and I need to get the parameters' values.

The object my program is given will look like this:

Object = """{{objectName|
parameter1=random text|
parameter2=that may or may not|
parameter3=contain any letter (well, almost)|
parameter4=this is some [[problem|problematic text]], Houston, we have a problem!|
otherParameters=(order of parameters is random, but their name is fixed)}}"""

(all parameters might or might not exist)

I am trying to get the properties values.

In the first 3 lines, its pretty easy. a simple regex will find it:

if "parameter1" in Object:
    parameter1 = re.split(r"parameter1=(.*?)[\|\}]", Object)[1]

if "parameter2" in Object:
    parameter2 = re.split(r"parameter2=(.*?)[\|\}]", Object)[1]

and so on.

The problem is with parameter4, the above regex ( property4=(.*?)[\\|\\}] ) will only return this is some [[problem , since the regex stops at the vertical bar.

Now here is the thing: vertical bar will only appear as part of the text inside "[[]]".

For example, parameter1=a[[b|c]]d might appear, but parameter1=a|bc| will never appear.

I need a regex which will stop at vertical bar, unless it is inside double square brackets. So for example, for parameter4, I will get this is some [[problem|problematic text]], Houston, we have a problem!

Answer 1

Worked here when I removed the "?":

parameter4 = re.split(r"parameter4=(.*)[\|\}]", object_)[1]

I also changed the name of the variable to "object_" because "object" is a built-in object in Python

Best.

Answer 2

Apparently, there is no perfect solution.

For other readers possibly reading this question in the future, the closest solution is, as pointed by Wiktor Stribiżew in the comments, parameter4=([^[}|]*(?:\\[\\[.*?]][^[}|]*)*) .

This regex will only work if the param text does not contain any single [ , } and | but may contain [[...]] sub-strings.

If you want to understand this regex better, you might want to have a look here: https://regex101.com/r/bWVvKg/2