在Hibernate 4中获取错误意外令牌

Question

Hi I developing a web app using spring mvc 3 and hibernate 4. I'm using annotations for all config.

When I try to select a entity I get an error:

DaoException: unexpected token: MEMBER near line 1, column 37 [from clanwar.model.ClanMember where MEMBER = :member]
at clanwar.dao.impl.ClanMemberDao.findByPlayerId(ClanMemberDao.java:71)

If I do the query with .createSQLQuery() hibernate return me an Object[] instance of ClanMember entity.

Method in DAO:

    @Repository
    @Transactional

    ...

    @Override
    public ClanMember findByPlayerId(int id) throws DaoException {

        ClanMember foundMember;

        try {
            foundMember = (ClanMember) getSession()
                .createQuery("from ClanMember where MEMBER = :member")
                .setParameter("member", id)
                .uniqueResult();
        } catch (Exception e) {
            throw new DaoException(e.getMessage());
        }

        return foundMember;
    }

    ...

Entity:

@Entity
@Table(name = "CLAN_MEMBERS")
public class ClanMember implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @ManyToOne
    @JoinColumn(name = "CLAN")
    private Clan clan;

    @Id
    @ManyToOne
    @JoinColumn(name = "MEMBER")
    private Player member;

    @ManyToOne
    @JoinColumn(name = "ROLE")
    private ClanRole role;

    public ClanMember() {}

    // Setters and getters

}

Table CLAN_MEMBERS:

+--------+---------+------+-----+---------+-------+
| Field  | Type    | Null | Key | Default | Extra |
+--------+---------+------+-----+---------+-------+
| CLAN   | int(11) | NO   | PRI | NULL    |       |
| MEMBER | int(11) | NO   | PRI | NULL    |       |
| ROLE   | int(11) | NO   |     | 1       |       |
+--------+---------+------+-----+---------+-------+

What I'm doing wrong? Thanks in advance.

Answer 1

Your query should be like following:

from ClanMember where member = :member

Therefore your code to get member should look like following:

foundMember = (ClanMember) getSession()
                .createQuery("from ClanMember where member = :member")
                .setParameter("member", id)
                .uniqueResult();

And also note that id which you pass should be an instance of Player class.

Answer 2

member is a reserved word in HQL. Escape it by adding a table alias.

Also, since member is of type Player , when your where clause contains member you need to provide a parameter of type Player . Alternatively if you want to provide the ID as you're doing, you need to explicitly search for the id :

So either:

 foundMember = (ClanMember) getSession()
            .createQuery("from ClanMember c where c.member = :member")
            .setParameter("member", someInstanceOfPlayer);
            .uniqueResult();

or

 foundMember = (ClanMember) getSession()
            .createQuery("from ClanMember c where c.member = :member")
            .setParameter("member", idOfAPlayer);
            .uniqueResult();