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Scala函数文字中=>(向右双箭头)运算符的链接是什么意思?

[英]What is the meaning of the chaining of => (rightward double arrow) operator in Scala's function literal?

What is the meaning of chaining of => operator like in this code: 像这样的代码中=>运算符的链接是什么意思:

val a = Array("I", "love", "Scala Johnson")
a.foreach {
    x => y: String => println(x)
}

It printed out nothing. 它什么也没打印出来。

So what happened? 所以发生了什么事? Does the x lost in compilation? x是否在编译中丢失?

If I removed String type declaration from y parameter: 如果我从y参数中删除了String类型声明:

x => y => println(x)

I got "missing parameter type" compile error. 我收到"missing parameter type"编译错误。

Then I did an experiment: 然后我做了一个实验:

val hotFunc: Int => Int => Unit = x => y => println(x * y)
hotFunc(2)(11)

It printed out 22 . 它打印了22

So, does the chaining of => mean currying? 那么, =>的链接是否意味着currying?

UPDATE: 更新:

The 3rd case: 第三种情况:

def readFile[T](f: File)(handler: FileInputStream => T): T = {
    val resource = new java.io.FileInputStream(f)
    try {
        handler(resource)
    } finally {
        resource.close()
    }
}

val bs = new Array[Byte](4)

readFile(new File("Slurp.scala")) {
    input => b: Byte => println("Read: " + (input.read(bs) + b))
}

It's same with 1st example, printed out nothing. 与第一个示例相同,什么也不打印。

The => is right associative, so in your first example you are calling a function with the values of a , which return a function String=>Unit (but that never get caught, get converted implicitly to Unit because of foreach ). =>是右结合的,所以在你的第一个例子中,你正在呼吁与值的函数a ,它会返回一个函数String=>Unit (但从来没有被抓住,获得隐式转换为Unit ,因为foreach )。 Probably it would be more clear with parentheses: 用括号可能会更清楚:

x => ((y: String) => println(x))

which turned to 变成了

x => ((y: String) => println(x); ())

in foreach , because it expects T => Unit . foreach ,因为它期望T => Unit

Chaining of => (without parentheses) is kind of currying, yes. => (不带括号)的链接有点麻烦,是的。

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