用Java处理命令行文件路径参数的最佳方法

Question

I'd like to pass a file path argument to my application in a relative form, eg ~/test.conf or ../test.conf , but i can't get a proper full file path, though i've tried it with old java.io and new java.nio Files/Paths . Is there a general way to get a resolved file path without large amount of code? It would be fine for the solution to work only in unix envs like OsX or Debian.

Update

With a provided argument like ~/test.conf in case of getAbsolutePath it returns a path with a prefixed current folder - /Users/currentUser/Projects/Personal/TestProject/~/text.conf . Canonical path returns the same.

Answer 1

The hard bit here is dealing with POSIX home directories, and sure you deal with ~otheruser/dir/test.conf too (if you want to do it properly).

Luckily that's covered in How to handle ~ in file paths .

TL;DR - use something like:

path.replace("~/", System.getProperty("user.home") + "/");

Once you've done that, and as others have commented, you can just use standard java.io methods (including getCanonicalPath() ).