如何使用正则表达式findall列表

Question

so i'm a js trainee and at my internship someone asked me to do something on the python code, but i never did something on Python so i'm a bit lost.. I would like to separate a string in differents block.

here is what i have :

    buffer = """
#<start>
    idothings
#</start>
#<params>
    otherthings
#</params>
#<end>
    andifinish
#</end>

what i would like is a regex that separate this string in differents parts :

separatedString = [["#<start>,"idothings","#</start>"],["#<params>,"otherthings","#</params>"],["#<end>,"andifinish","#</end>"]]

what i tried to do is that :

def getStructure(string):

    separatedString = re.findall('(#<.+?>)(.|\n)+?(#<\/.+?>)', string)
    return

but this gave me a list... and i don't understand how do i navigate through a list in python ...

[("#<start>", '\n', '#</start>'), ('#<azeaze>', '\n', '#</azeaze>'), ('#<sgdfs>', 'x', '#</sgdfs>')]

i tried :

print '\n'.join(["%s a %s et %s" %(p1,p2,p3) for p1, strings in separatedString ])

but it game me an error "too many values to unpack"

Can someone show me how i can do this?

Answer 1

Your print statement is a little faulty . Try this instead

print '\n'.join(["%s a %s et %s" %(p1,p2,p3) for p1, p2, p3 in separatedString ])

You are getting an error because, you are trying to get two values from a tuple having three elements

for p1, strings in separatedString 

Here separatedString has 3 elements in each of its members

Answer 2

buffer = """#<start>
    idothings
#</start>
#<params>
    otherthings
#</params>
#<end>
    andifinish
#</end>"""

spl = buffer.splitlines()
print([spl[i:i+3] for i in range(0,len(spl),3)])
[['#<start>', '    idothings', '#</start>'], ['#<params>', '    otherthings', '#</params>'], ['#<end>', '    andifinish', '#</end>']]




spl = buffer.splitlines()
sliced = [spl[i:i+3] for i in range(0,len(spl),3)]

for a,b,c in sliced:
    print(a.strip(),b.strip(),c.striip())
('#<start>', 'idothings', '#</start>')
('#<params>', 'otherthings', '#</params>')
('#<end>', 'andifinish', '#</end>')