[英]Ansible or Python, how to use regex_findall on a list to return words that start with a certain pattern
I am mainly using this in ansible but I figured its similar in python.我主要在 ansible 中使用它,但我认为它在 python 中类似。 So I have a list of strings which I need to extract words from it that start with a certain pattern.
所以我有一个字符串列表,我需要从中提取以某种模式开头的单词。 For example if I have the following:
例如,如果我有以下内容:
list1: ['water_3gallons_6/20/22 490832', 'applejuice_1liter_6/18/22 490833', 'soda_2liters_6/22/22 490834', 'water_1gal_today 490835']
# and lets say I only want to pull the words that start with water (ignoring the 490832 part)
# meaning it should return this list: ['water_3gallons_6/20/22','water_1gal_today']
# I was using the following 2 codes and it was returning an empty list
- name: "Create list of words that start with water from list1 variable"
set_fact:
start_with_water: "{{ list1 |regex_findall('^water') }}" # RETURNED EMPTY LIST
- name: "Create list of words that start with water from list1 variable"
set_fact:
start_with_water: "{{ list1 |regex_findall('\\Awater') }}" # RETURNED EMPTY LIST TOO
edit: updated with the new requirement编辑:根据新要求更新
While Frenchy's answer isn't wrong, it will be inherently slower and is a lot more verbose than the way Jinja2 wants that done which is via the |select
filter , designed for working with list items:虽然 Frenchy 的回答没有错,但它本质上会比 Jinja2 想要通过
|select
filter完成的方式更慢并且更冗长,该过滤器专为处理列表项而设计:
- set_fact:
start_with_water: >-
{{ list1 | select('match', '^water')
| map('regex_findall', '([^ ]+) .*')
| map('first')
| list }}
produces生产
{
"ansible_facts": {
"start_with_water": [
"water_3gallons_6/20/22",
"water_1gal_today"
]
},
"changed": false
}
In case you were curious why your approach with regex_findall
did not do what you expected, it's because that filter wants a string input, so jinja2 helpfully(?) coerced the list[str]
into str
by calling str(list1)
and fed that into the filter which didn't match any "start of line" like you expected如果您好奇为什么您使用
regex_findall
的方法没有达到您的预期,那是因为该过滤器需要一个字符串输入,所以 jinja2 有帮助(?)通过调用str(list1)
将list[str]
强制转换为str
并将其输入过滤器与您预期的任何“行首”都不匹配
regex_findall
is used on string: regex_findall
用于字符串:
tasks:
- name: get data
set_fact:
start_with_water: "{{ start_with_water | d([]) + [item] }}"
loop: "{{ list1 }}"
when: item | regex_findall('^water')
- name: display
debug:
msg: "{{ start_with_water }}"
result:结果:
ok: [localhost] => {
"msg": [
"water_3gallons_6/20/22 490832",
"water_1gal_today 490835"
]
}
to avoid when
condition, you could use select
directly on list:为避免
when
条件,您可以直接在列表中使用select
:
tasks:
- set_fact:
start_with_water: "{{ list1|select('regex', '^water')|list }}"
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