如何使用php从mySQL表中获取一行数据？

Question

Here is an example of the current PHP code I have. I simply want to grab one row from the table, but it returns this error:

Call to a member function fetch_assoc() on a non-object

Any insight would be appreciated.

$pathname = "C:\Users\BL\Documents\GitHub\Moozik\music";
$files = scandir($pathname);
$server = "localhost";
$user = "root";
$pass = "";

while ($files[0] == "." || $files[0] == "..") {
    array_shift($files);
}

print_r($files);
$song = $pathname . '\\' . $files[0];

$conn = new mysqli($server, $user, $pass);

if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT song_path FROM song_data";
$result = mysqli_query($conn, $sql);

while($row = $result->fetch_assoc()) {
    $its = $row["song_path"];
    printf($its);
}

mysqli_close($conn);

Answer 1

Point 1 :

You have mixed mysqli Object-oriented and Procedural methods...Use any one

Point 2:

$conn = new mysqli($server, $user, $pass); 
// Here You missed database to be selected

Point 3:

$result = mysqli_query($conn, $sql); // Used procedural method But Connection is by Object Oriented method

here is a full object oriented method

$conn = new mysqli($server, $user, $pass, $database);

if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT song_path FROM song_data";
$result = $conn->query($sql);

while($row = $result->fetch_assoc()) {
           $its = $row["song_path"];
            echo $its;
    }


$conn->close();

Answer 2

You can use

$row=mysqli_fetch_array($result)

You don't even have to use while since you wanna fetch only one row. IF you wanna fetch more than one row, then you can use the while.

Answer 3

You can use this.

$row=mysqli_fetch_row($result)

It will fetches the one row from result set..

Hope this will help.!