[英]How do I get one row of data from mySQL table using php?
这是我当前拥有的PHP代码的示例。 我只想从表中获取一行,但它返回此错误:
Call to a member function fetch_assoc() on a non-object
任何见识将不胜感激。
$pathname = "C:\Users\BL\Documents\GitHub\Moozik\music";
$files = scandir($pathname);
$server = "localhost";
$user = "root";
$pass = "";
while ($files[0] == "." || $files[0] == "..") {
array_shift($files);
}
print_r($files);
$song = $pathname . '\\' . $files[0];
$conn = new mysqli($server, $user, $pass);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT song_path FROM song_data";
$result = mysqli_query($conn, $sql);
while($row = $result->fetch_assoc()) {
$its = $row["song_path"];
printf($its);
}
mysqli_close($conn);
第一点:
You have mixed mysqli Object-oriented and Procedural methods...Use any one
第2点:
$conn = new mysqli($server, $user, $pass);
// Here You missed database to be selected
第三点
$result = mysqli_query($conn, $sql); // Used procedural method But Connection is by Object Oriented method
这是一个完整的面向对象的方法
$conn = new mysqli($server, $user, $pass, $database);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT song_path FROM song_data";
$result = $conn->query($sql);
while($row = $result->fetch_assoc()) {
$its = $row["song_path"];
echo $its;
}
$conn->close();
您可以使用
$row=mysqli_fetch_array($result)
由于您只想获取一行,因此您甚至不必使用任何时间。 如果您想获取多个行,则可以使用while。
您可以使用它。
$row=mysqli_fetch_row($result)
它将从结果集中获取一行。
希望这会有所帮助。
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