如何在Typescript中为私有类成员声明参数和返回类型？

Question

I am attempting to convert some code from vanilla javascript, and part of that requires storing a function as a private class member. I am attempting to figure out the proper syntax for this, but can't seem to get it right.

What I want to ultimately say is:

module MyModule {
    export class MyClass {
        private myLocalReferenceToTheFunction: Function<T>(serverCall: (...args: any[]) => ng.IPromise<T>): ng.IPromise<T>;

        constructor(myOtherService: OtherService) {
           this.myLocalReferenceToTheFunction = myOtherService.serviceFunction;
        }
    }
}

What is the proper syntax for the private myLocalReferenceToTheFunction... line?

Tangentially, if this is the totally wrong way to go about doing this, I'd appreciate knowing. Really, my only end goal is to be able to use myLocalReferenceToTheFunction in functions inside of MyClass .

Answer 1

Looks to me like this is what you're trying to do:

module MyModule {
    export class MyClass<T> {
        private myLocalReferenceToTheFunction: (serverCall: (...args: any[]) => ng.IPromise<T>) => ng.IPromise<T>;

        constructor(myOtherService: OtherService) {
            this.myLocalReferenceToTheFunction = myOtherService.serviceFunction;
        }
    }
}

Hard for me to tell for sure that this is what you need though.
Seeing the definition of OtherService would help.

Answer 2

Something like this?

var MyModule = function() {
    return {
        MyClass : function () {
            var myLocalReferenceToTheFunction;
            var constructor = function(myOtherService) {
                myLocalReferenceToTheFunction = myOtherService;
            };
            return constructor;
        }()
    };
}();