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如何使用python正则表达式匹配中间的数字?

[英]How to match a number in middle using python regular expression?

I am trying to put PASS/FAIL criteria for the following command output. 我试图为以下命令输出输入通过/失败标准。

router-7F2C13#show app stats gmail on TEST/switch1234-15E8CC
--------------------------------------------------------------------------------
     APPLICATION           BYTES_IN         BYTES_OUT           NUM_FLOWS
--------------------------------------------------------------------------------
  gmail                0                 0                  0
--------------------------------------------------------------------------------
router-7F2C13#

I need to match only "NUM_FLOWS". 我只需要匹配“ NUM_FLOWS”。 If its "zero" then it will be considering as FAIL. 如果其为“零”,则将其视为失败。 If its "Greater than or equal to 1" then it will be considering as PASS. 如果其“大于或等于1”,则将其视为PASS。

FAIL criteria example:
======================

router-7F2C13#show app stats gmail on TEST/switch1234-15E8CC
--------------------------------------------------------------------------------
     APPLICATION           BYTES_IN         BYTES_OUT           NUM_FLOWS
--------------------------------------------------------------------------------
  gmail                0                 0                  0
--------------------------------------------------------------------------------
router-7F2C13#



PASS criteria example: (Greater than or equal to 1)
======================

router-7F2C13#show app stats gmail on TEST/switch1234-15E8CC
--------------------------------------------------------------------------------
     APPLICATION           BYTES_IN         BYTES_OUT           NUM_FLOWS
--------------------------------------------------------------------------------
  gmail                0                 0                  1
--------------------------------------------------------------------------------
router-7F2C13#

Please guide me on how to do this. 请指导我如何执行此操作。

NUM_FLOWS\n-+[\s\S]*?(\d+)\s*-+

You can try this.Grab the capture. 您可以尝试此操作。

See demo. 参见演示。

https://www.regex101.com/r/bC8aZ4/7 https://www.regex101.com/r/bC8aZ4/7

x="""router-7F2C13#show app stats gmail on TEST/switch1234-15E8CC
--------------------------------------------------------------------------------
     APPLICATION           BYTES_IN         BYTES_OUT           NUM_FLOWS
--------------------------------------------------------------------------------
  gmail                0                 0                  0
--------------------------------------------------------------------------------
router-7F2C13#
---------------------------------------------------------------
router-7F2C13#"""
if int(re.findall(r"NUM_FLOWS\n-+[\s\S]*?(\d+)\s*-+",x)[0]):
      print "pass"
else:
      print "fail"

Since this is command output you can pipe the output of the command into a Python script and process it with the fileinput module: 由于这是命令输出,因此您可以将命令的输出通过管道fileinput到Python脚本中,并使用fileinput模块进行处理:

import fileinput
for line in fileinput.input():
    if fileinput.filelineno() == 5:
        # split the line on whitespace, and take the last item.
        x = int(line.split()[-1])
        print('PASS' if x else 'FAIL')
        break # so it won't process more lines past 5

Result with pass.xxx containing your pass criteria and fail.xxx containing your fail criteria: 结果为pass.xxx包含通过标准,而fail.xxx包含失败标准:

c:\> type fail.xxx | check.py
FAIL

c:\> type pass.xxx | check.py
PASS

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