如何使用python正则表达式匹配中间的数字？

Question

我试图为以下命令输出输入通过/失败标准。

router-7F2C13#show app stats gmail on TEST/switch1234-15E8CC
--------------------------------------------------------------------------------
     APPLICATION           BYTES_IN         BYTES_OUT           NUM_FLOWS
--------------------------------------------------------------------------------
  gmail                0                 0                  0
--------------------------------------------------------------------------------
router-7F2C13#

我只需要匹配“ NUM_FLOWS”。 如果其为“零”，则将其视为失败。 如果其“大于或等于1”，则将其视为PASS。

FAIL criteria example:
======================

router-7F2C13#show app stats gmail on TEST/switch1234-15E8CC
--------------------------------------------------------------------------------
     APPLICATION           BYTES_IN         BYTES_OUT           NUM_FLOWS
--------------------------------------------------------------------------------
  gmail                0                 0                  0
--------------------------------------------------------------------------------
router-7F2C13#



PASS criteria example: (Greater than or equal to 1)
======================

router-7F2C13#show app stats gmail on TEST/switch1234-15E8CC
--------------------------------------------------------------------------------
     APPLICATION           BYTES_IN         BYTES_OUT           NUM_FLOWS
--------------------------------------------------------------------------------
  gmail                0                 0                  1
--------------------------------------------------------------------------------
router-7F2C13#

请指导我如何执行此操作。

Answer 1

NUM_FLOWS\n-+[\s\S]*?(\d+)\s*-+

您可以尝试此操作。

参见演示。

https://www.regex101.com/r/bC8aZ4/7

x="""router-7F2C13#show app stats gmail on TEST/switch1234-15E8CC
--------------------------------------------------------------------------------
     APPLICATION           BYTES_IN         BYTES_OUT           NUM_FLOWS
--------------------------------------------------------------------------------
  gmail                0                 0                  0
--------------------------------------------------------------------------------
router-7F2C13#
---------------------------------------------------------------
router-7F2C13#"""
if int(re.findall(r"NUM_FLOWS\n-+[\s\S]*?(\d+)\s*-+",x)[0]):
      print "pass"
else:
      print "fail"

Answer 2

由于这是命令输出，因此您可以将命令的输出通过管道fileinput到Python脚本中，并使用fileinput模块进行处理：

import fileinput
for line in fileinput.input():
    if fileinput.filelineno() == 5:
        # split the line on whitespace, and take the last item.
        x = int(line.split()[-1])
        print('PASS' if x else 'FAIL')
        break # so it won't process more lines past 5

结果为pass.xxx包含通过标准，而fail.xxx包含失败标准：

c:\> type fail.xxx | check.py
FAIL

c:\> type pass.xxx | check.py
PASS