Linux：复制多个文件并删除它的扩展名

Question

I have got a directory containing files of type *.cpp.So i would like to copy each file in the directory and to paste it in the same directory by using

 cp -a *.cpp 

with an option to remove the .cpp while pasting.Is it possible ?

Answer 1

Here is a simple bash script. This script assumes that the file name only contains one "." character and splits based on that.

#!/bin/sh

for f in *.cpp; do

#This line splits the file name on the delimiter "."
baseName=`echo $f | cut -d "." -f 1`
newExtension=".new"

cp $f $baseName$newExtension

done

Answer 2

You can do this just by means of bash parameter extension, as mentioned in the bash manual:

${parameter%%word} Remove matching suffix pattern. The word is expanded to produce a pattern just as in pathname expansion. If the pattern matches a trailing portion of the expanded value of parameter, then the result of the expansion is the expanded value of parameter with the shortest matching pattern (the ``%'' case) or the longest matching pattern (the ``%%'' case) deleted.
...

for i in *.cpp
do
     cp -a $i ${i%%.cpp}
done

Answer 3

Can use rename , optionally with -f to force rewrite existing files.

rename -f 's/\.ext$//' *.ext

To preview actions, but don't change files, use -n switch (No action).

This is not copy but move :-(