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DICT功能在RNA翻译程序中不起作用

[英]DICT function not working in RNA translate program

I was wondering what could be wrong with the code below and why I am getting an error KeyError: '[' ? 我想知道下面的代码可能出什么毛病,为什么我得到一个错误KeyError:'['?

The program is meant to translate the input DNA sequence to an RNA sequence and then from the RNA sequence stored in RNA [] produce the AMINO ACID sequence from the dict. 该程序旨在将输入的DNA序列翻译为RNA序列,然后从存储在RNA中的RNA序列[]从dict生成AMINO ACID序列。

Thanks 谢谢

DNA = "ACAAGATGCCATTGTCCCCCGGCCTCCTGCTGCTGCTGCTCTCCGGGGCCACGGCCACCGCTGCCCTGC"
RNA = []

AMINO_ACIDS = {"UUU":"F", "UUC":"F", "UUA":"L", "UUG":"L",
    "UCU":"S", "UCC":"s", "UCA":"S", "UCG":"S",
    "UAU":"Y", "UAC":"Y", "UAA":"STOP", "UAG":"STOP",
    "UGU":"C", "UGC":"C", "UGA":"STOP", "UGG":"W",
    "CUU":"L", "CUC":"L", "CUA":"L", "CUG":"L",
    "CCU":"P", "CCC":"P", "CCA":"P", "CCG":"P",
    "CAU":"H", "CAC":"H", "CAA":"Q", "CAG":"Q",
    "CGU":"R", "CGC":"R", "CGA":"R", "CGG":"R",
    "AUU":"I", "AUC":"I", "AUA":"I", "AUG":"M",
    "ACU":"T", "ACC":"T", "ACA":"T", "ACG":"T",
    "AAU":"N", "AAC":"N", "AAA":"K", "AAG":"K",
    "AGU":"S", "AGC":"S", "AGA":"R", "AGG":"R",
    "GUU":"V", "GUC":"V", "GUA":"V", "GUG":"V",
    "GCU":"A", "GCC":"A", "GCA":"A", "GCG":"A",
    "GAU":"D", "GAC":"D", "GAA":"E", "GAG":"E",
    "GGU":"G", "GGC":"G", "GGA":"G", "GGG":"G",}

RNA_2 = str(RNA)
for char in DNA:
    if char == "G":
        RNA.append("C")
    elif char == "C":
        RNA.append("G")
    elif char == "A":
        RNA.append("U")
    elif char == "T":
        RNA.append("A")

translated = ''.join(AMINO_ACIDS[i] for i in RNA_2)

print("DNA sequence: " + DNA)
print()
print("Length of DNA sequence in base pairs: " + str(len(DNA)))
print()
print("RNA sequence of DNA sequence: " +("".join(RNA)))
print()
print("AMINO ACID sequence: " + str(translated))

You don't need RNA_2 , but you do need a way to split an RNA string into chunks of three character strings. 您不需要RNA_2 ,但确实需要一种将RNA字符串分成三个字符串的块的方法。 Borrowing a chunk function from this post : 这篇文章中借用一个块函数:

def chunks(l, n):
    """ Yield successive n-sized chunks from l.
    """
    for i in xrange(0, len(l), n):
        yield l[i:i+n]

DNA = "ACAAGATGCCATTGTCCCCCGGCCTCCTGCTGCTGCTGCTCTCCGGGGCCACGGCCACCGCTGCCCTGC"
RNA = []

AMINO_ACIDS = {"UUU":"F", "UUC":"F", "UUA":"L", "UUG":"L",
    "UCU":"S", "UCC":"s", "UCA":"S", "UCG":"S",
    "UAU":"Y", "UAC":"Y", "UAA":"STOP", "UAG":"STOP",
    "UGU":"C", "UGC":"C", "UGA":"STOP", "UGG":"W",
    "CUU":"L", "CUC":"L", "CUA":"L", "CUG":"L",
    "CCU":"P", "CCC":"P", "CCA":"P", "CCG":"P",
    "CAU":"H", "CAC":"H", "CAA":"Q", "CAG":"Q",
    "CGU":"R", "CGC":"R", "CGA":"R", "CGG":"R",
    "AUU":"I", "AUC":"I", "AUA":"I", "AUG":"M",
    "ACU":"T", "ACC":"T", "ACA":"T", "ACG":"T",
    "AAU":"N", "AAC":"N", "AAA":"K", "AAG":"K",
    "AGU":"S", "AGC":"S", "AGA":"R", "AGG":"R",
    "GUU":"V", "GUC":"V", "GUA":"V", "GUG":"V",
    "GCU":"A", "GCC":"A", "GCA":"A", "GCG":"A",
    "GAU":"D", "GAC":"D", "GAA":"E", "GAG":"E",
    "GGU":"G", "GGC":"G", "GGA":"G", "GGG":"G",}

for char in DNA:
    if char == "G":
        RNA.append("C")
    elif char == "C":
        RNA.append("G")
    elif char == "A":
        RNA.append("U")
    elif char == "T":
        RNA.append("A")


translated = ''.join(AMINO_ACIDS[i] for i in chunks("".join(RNA), 3))

print("DNA sequence: " + DNA)
print()
print("Length of DNA sequence in base pairs: " + str(len(DNA)))
print()
print("RNA sequence of DNA sequence: " +("".join(RNA)))
print()
print("AMINO ACID sequence: " + str(translated))

Result: 结果:

DNA sequence: ACAAGATGCCATTGTCCCCCGGCCTCCTGCTGCTGCTGCTCTCCGGGGCCACGGCCACCGCTGCCCTGC
()
Length of DNA sequence in base pairs: 69
()
RNA sequence of DNA sequence: UGUUCUACGGUAACAGGGGGCCGGAGGACGACGACGACGAGAGGCCCCGGUGCCGGUGGCGACGGGACG
()
AMINO ACID sequence: CSTVTGGRRTTTTRGPGAGGDGT

A little more about your original error. 有关原始错误的更多信息。 I think you may be misunderstanding what RNA_2 = str(RNA) does. 我认为您可能会误解RNA_2 = str(RNA)作用。 It doesn't mean "now and forever, RNA_2 will be the string version of RNA, and keep up-to-date whenever RNA changes". 这并不意味着“现在和永远,RNA_2将成为RNA的字符串版本,并在RNA发生变化时保持最新”。 It means "Take the contents of RNA at this instant in time, turn it into a string, and that's what RNA_2 will be, even when RNA changes later". 它的意思是“立即获取RNA的内容,将其变成字符串,这就是RNA_2的含义,即使RNA稍后发生变化也是如此”。 So RNA_2 will be "[]" even after you've appended values to RNA. 因此,即使您将值附加到RNA后, RNA_2也将是“ []”。 This is the source of your KeyError. 这是您的KeyError的来源。 "[" is the first character of RNA_2 , and "[" is not present in AMINO_ACIDS . “ [”是RNA_2的第一个字符,“ [”在AMINO_ACIDS不存在。

But even if you did RNA_2 = str(RNA) after you finished your appending loop, I don't think it would give you the result you would want. 但是,即使完成附加循环之后执行RNA_2 = str(RNA) ,我也不认为它会给您想要的结果。 It would be ['U', 'G', 'U', 'U', 'C', ... rather than "UGUUC" . 它应该是['U', 'G', 'U', 'U', 'C', ...而不是"UGUUC" If you want the latter, you ought to use "".join(RNA) rather than str(RNA) . 如果需要后者, "".join(RNA)使用"".join(RNA)而不是str(RNA)

But even if you use "".join(RNA) , iterating through it and trying to access AMINO_ACIDS won't work, because AMINO_ACID 's keys are all three characters long, and iterating over a string gives you one character at aa time. 但是,即使您使用"".join(RNA) ,也无法对其进行迭代并尝试访问AMINO_ACIDS ,因为AMINO_ACID的键都是三个字符长,并且在字符串上进行迭代可以一次给您一个字符。 That's where chunk comes in, letting you iterate three characters at a time. 那就是chunk来历,让您一次迭代三个字符。

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