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numpy排序数组(稀疏)

[英]Numpy sorting array (sparse)

I'm trying to work out why this code doesn't sort the array... 我试图弄清楚为什么这段代码不对数组排序...

Arbitrary vector. 任意向量。

x = array([[3, 2, 4, 5, 7, 4, 3, 4, 3, 3, 1, 4, 6, 3, 2, 4, 3, 2]])
xCoo = sps.coo_matrix(x)
perm = np.argsort(x)
xCoo.col = perm[xCoo.col]
print(xCoo.toarray()) # array([3, 2, 4, 5, 7, 4, 3, 4, 3, 3, 1, 4, 6, 3, 2, 4, 3, 2])

I'm not sure what I've misunderstood. 我不确定我误会了什么。 What's the correct way to do this? 正确的方法是什么?

Thank you. 谢谢。

PS I'm aware that I can just call sort on the array; PS,我知道我可以在数组上调用sort。 however, I went to apply this same permutation over and over again. 但是,我又一次又一次地应用了相同的排列。

The first complication is the np.argsort(x) returns a 2d array. 第一个复杂之处是np.argsort(x)返回2d数组。 Lets do the sort on flattened x to get a simpler 1d perm : 让我们对展平的x进行排序以获得更简单的1d perm

In [1118]: perm=np.argsort(x,None)

In [1119]: perm
Out[1119]: 
array([10, 17,  1, 14, 13,  9, 16,  0,  6,  8,  5, 11,  2, 15,  7,  3, 12,
        4], dtype=int32)

this sorts x as we expect, right? 就像我们期望的那样对x排序,对不对?

In [1120]: x[:,perm]
Out[1120]: array([[1, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 6, 7]])

now apply it in the same way to xCoo , except we have to convert it to lil format. 现在将其以相同的方式应用于xCoo ,除了我们必须将其转换为lil格式。 coo format isn't subscriptable: coo格式不可下标:

In [1121]: xCoo.tolil()[:,perm].A
Out[1121]: array([[1, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 6, 7]], dtype=int32)

To apply perm directly to the attributes of xCoo , we need to do another sort: 要将perm直接应用于xCoo的属性,我们需要执行另一种排序:

xCoo.col = np.argsort(perm)[xCoo.col]   # <====

This works for multirow xCoo with zeros. 这适用于带有零的多行xCoo

You can also sort the data: 您还可以对数据进行排序:

xCoo.data = xCoo.data[perm[xCoo.col]]

These work here, but they need more testing. 这些在这里有效,但是需要更多测试。

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